使用Cobertura时Spring Autowiring失败

Question

@Transactional
public interface UserRepository extends CrudRepository<User, Long> {

    public User findByCrmId(String crmIdId);
}

@Service
@Transactional
public class UserService extends TraceablePersistenceService<User, UserRepository> {

    @Autowired
    UserRepository repository;

    @Transactional
    public Iterable<User> findAll() {
        return repository.findAll();
    }

    public User findOne(Long id) {
        return repository.findOne(id);
    }
}

我们的配置在

@Configuration
@EnableTransactionManagement(proxyTargetClass=true)
@EnableJpaRepositories(basePackages = {"com.dnb.components.storage.repository"})
@Profile("inmemory")
public class InMemoryStandaloneStorageConfig extends BasicJpaStorageConfig {

....

（为简洁起见略去）

UserResource.java：

@Component
@Path(UserResource.uri)
public class UserResource extends AbstractResource {
    public final static String uri = BASE_URI + "/users";

    @Override
    public String getURI() {
        return BASE_URI + uri;
    }

    @Autowired
    private UserService userService;

Answer 1

通常，我们不注入具体的类，而是注入接口。这是我的建议。

a.将UserService重构为UserServiceImpl类

b.创建UserService接口