将一个tomcat应用程序的不安全请求重定向到安全端口，而不重定向另一个应用程序的请求

Question

我有两个在Tomcat7.0下运行的web应用程序

1. https://secure.example.com:8443
2. http://insecure.example.com:8080

null

是否可以用单个tomcat实例来配置它？

Answer 1

这可以通过在conf/server.xml中设置单独的“service”元素来实现。

例如，您有

<Service name="Catalina">
  <Connector port="8080" protocol="HTTP/1.1" connectionTimeout="20000" />
  <Engine name="Catalina" defaultHost="insecure.example.com">
      <Host name="insecure.example.com"  appBase="insecure" unpackWARs="true" autoDeploy="true">
      </Host>
  </Engine>
</Service>

现在增加附加服务部分

<Service name="SecureApps">
  <Connector port="8443" protocol="HTTP/1.1" SSLEnabled="true"
           maxThreads="150" scheme="https" secure="true"
            keystoreFile="/usr/local/tomcat/keys/keystore.p12" keystorePass="mySecret" keystoreType="pkcs12"
           clientAuth="false" sslProtocol="TLS" />
  <Engine name="SecureEngine" defaultHost="secure.example.com">
      <Host name="secure.example.com"  appBase="secure" unpackWARs="true" autoDeploy="true">
      </Host>
  </Engine>
</Service>

<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">

    <display-name>Redirect to secure port</display-name>
    <description>
        This is a simple web application which redirects you to secure port
    </description>

    <servlet>
        <servlet-name>RedirectServlet</servlet-name>
        <servlet-class>com.mycompany.RedirectServlet</servlet-class>
    </servlet>

    <servlet-mapping>
        <servlet-name>RedirectServlet</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

</web-app>

重定向Servlet.java

import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

public class RedirectServlet extends HttpServlet
{
    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws IOException
    {
        String url = "https://secure.example.com:8443/";

        response.sendRedirect(url);

    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws IOException
    {
        String url = "https://secure.example.com:8443/";

        response.sendRedirect(url);

    }
}