无法使用xstream将xml字符串反序列化为扩展GenericType的对象

Question

首先，我想展示反序列化xml字符串的核心代码

    public XMLClient<T> xmlToClient(String xmlString,T t) throws Exception{
    //according to the generic class's name,insert the name after input tag
    //to make the xstream to know which class is going to deserialize to
        String insertClassName = t.getGenericTypeRecord();
        xmlString.replaceAll("<INPUT>", "<INPUT input."+insertClassName+">");
        XMLClient<T> xmlClient = new XMLClient<T>();
        XStream xs = new XStream(new DomDriver());
        xs.processAnnotations(XMLClient.class);
        xmlClient = (XMLClient<T>)xs.fromXML(xmlString);
        logger.info(xmlString);
        return xmlClient;
    }

T是从超级基类扩展的a类。就像

xmlClient = (XMLClient<T>)xs.fromXML(xmlString);

我希望你能理解我的想法，我真的对这些genericType和xstream转换感到困惑。谢谢。

Answer 1

xs.processAnnotations(XMLClient.class);

应将此行编辑为

xs.processAnnotations(XMLClient.class);
xs.processAnnotations(XMLClientsSuperClass.class);