未调用自定义Spring UserDetailsService

Question

我试图为当前登录的用户添加一些自定义数据，所以我发现我可以实现自己的UserDetailsService并将其插入Spring中，但它从未被调用，我总是以用户名字符串的形式获得主体。

我有我的UserDetailsService实现：

@Service
public class UserDetailServiceImpl implements UserDetailsService {

  @Override
  public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
    ...
  }
}

我的UserDetails实现：

import org.springframework.security.core.userdetails.User;

public class LoggedInUser extends User {
...
}

并尝试通过多种方式在config（SecurityConfiguration）中设置它：

@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true)
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
      @Autowired
      private CustomAuthenticationProvider customAuthProvider;
      @Autowired
      private UserDetailsService userDetailServiceImpl;
      @Override
      protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.authenticationProvider(customAuthProvider);
        auth.userDetailsService(userDetailServiceImpl).passwordEncoder(passwordService.getPasswordEncoder());
      }
...
}

@Autowired
  protected void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
    auth.authenticationProvider(customAuthProvider);
    auth.userDetailsService(userDetailServiceImpl).passwordEncoder(passwordService.getPasswordEncoder());
  }

@Override
  @Bean
  public UserDetailsService userDetailsService() {
    return new UserDetailServiceImpl();
  }

Answer 1

ILya Cyclone的评论是找出错误所在的关键，在再次检查CustomAuthenticationProvider之后，我注意到，当返回数据时，您可以指定Principal，它不需要仅仅是用户名，但是您可以在那里添加自定义的UserDetails，因为自定义的UserDetailsService没有被调用，这是我假设它总是被调用的错误。

因此，最终这就足以使自定义AuthenticationProvider与自定义UserDetails:

@Service
public class CustomAuthenticationProvider implements AuthenticationProvider {

  @Autowired
  private UserService userService;

  @Autowired
  private PasswordService passwordService;

  @Override
  public Authentication authenticate(Authentication auth) throws AuthenticationException {
    String username = auth.getName();
    String password = auth.getCredentials().toString();

    User user = userService.getUserWithPermissionsByName(username);
    if (user == null) {
      throw new BadCredentialsException("invalid_username_or_pass");
    }

    if (!passwordService.passwordsMatch(password, user.getPassword())) {
      throw new BadCredentialsException("invalid_username_or_pass");
    }

    String[] permissions = user.getPermissions().stream().map((p) -> p.getName()).toArray(String[]::new);
    List<GrantedAuthority> grantedAuths = AuthorityUtils.createAuthorityList(permissions);
    return new UsernamePasswordAuthenticationToken(new LoggedInUser(user.getName(), user.getPassword(), true, true, true, true, grantedAuths, user.getId()),
        password, grantedAuths);
  }

  @Override
  public boolean supports(Class<?> auth) {
    return auth.equals(UsernamePasswordAuthenticationToken.class);
  }
}