Spring@ExceptionHandler、@ResponseBody将不序列化/封送响应

Question

@RequestMapping("/management")
@RestController
public class ManagementController {

    @Autowired
    private ManagementService managementService;

    @ExceptionHandler(DuplicateEntityException.class)
    @ResponseStatus(code = HttpStatus.CONFLICT)
    public ErrorDetail handleDuplicateEntityException(DuplicateEntityException ex) {
        return new ErrorDetail(ex.getMessage(), HttpStatus.CONFLICT.value());
    }

    @RequestMapping(value = "/user", method = RequestMethod.POST)
    @ResponseStatus(code = HttpStatus.CREATED)
    public User createUser(@RequestBody User user) {
        return managementService.createUser(user);
    } 
}

@XmlRootElement(name = "error")
@XmlAccessorType(XmlAccessType.FIELD)
public class ErrorDetail {

    @XmlElement(name = "message")
    private String message;

    @XmlAttribute(name = "status")
    private int status;

    public ErrorDetail(String message, int status) {
        super();
        this.message = message;
        this.status = status;
    }

    public String getMessage() {
        return message;
    }

    public int getStatus() {
        return status;
    }

    public void setMessage(String message) {
        this.message = message;
    }

    public void setStatus(int status) {
        this.status = status;
    }

}

public class DuplicateEntityException extends AAAException {

    private static final long serialVersionUID = 4223773548694193141L;

    public DuplicateEntityException(String message) {
        super(message);
    }

    public DuplicateEntityException(String message, Throwable cause) {
        super(message, cause);
    }

}

如有任何帮助，将不胜感激。

Answer 1

您似乎已经在控制器中添加了异常处理程序方法，因为如果您从该控制器本身获得异常时，将触发该方法。使用seperate类进行异常处理例如：

@ControllerAdvice
public class GlobalExceptionController {

@ExceptionHandler(DuplicateEntityException.class)
@ResponseBody
public ErrorDetail handleDuplicateEntityException(DuplicateEntityException ex) {
   ExceptionRepresentation  body = new ExceptionRepresentation(ex.getMessage());
   HttpStatus responseStatus = HttpStatus.CONFLICT;
   return new ResponseEntity<ExceptionRepresentation>(body,responseStatus);
}

在这里，使用@controlleradvice将对每个控制器应用异常处理。

最重要的是，您的方法应该抛出异常，以便@exceptionhandler工作，更改您的方法签名。

 public User createUser(@RequestBody User user) throw DuplicateEntityException{
    throw new DuplicateEntityException();
    }