在python上手动管理斧头[复制]

Question

我正试图做到这一点

但我以这个结束了

主要的想法是管理轴以在图中包含第三个子图，但我找不到一种方法。谁能帮个忙吗。

import matplotlib.pyplot as plt

import numpy as np

x = np.arange(-4*np.pi,4*np.pi,0.25)

np.sincx=np.sin(x)/x 

plt.figure(num=3, figsize=(7,5)) 
plt.subplot(3,2,1) 

plt.plot(x,np.sincx)

plt.subplot(3,2,2)

plt.plot(x,np.sincx,"ro")

fig = plt.figure()

ax = fig.add_axes((0.125,0.1,0.775,0.45))

plt.plot(x,np.sincx**2)

Answer 1

在代码中，您正在创建两个图形，一个带有两个顶部的图形，另一个带有底部的图形。您只需要创建一个包含多个子地块的子地块！

import numpy as np
import matplotlib.pyplot as plt

x = np.arange(-4*np.pi,4*np.pi,0.25)
np.sincx = np.sin(x)/x 

ax1 = plt.subplot(221)
ax1.plot(x,np.sincx)

ax2 = plt.subplot(222)
ax2.plot(x,-np.sincx,"ro")

ax3 = plt.subplot(212)
ax3.plot(x, np.sincx**2)

plt.show()

import numpy as np
import matplotlib.pyplot as plt

x = np.arange(-4*np.pi,4*np.pi,0.25)
np.sincx = np.sin(x)/x 

fig = plt.figure() 

ax1 = plt.subplot(221)
ax1.plot(x,np.sincx)

ax2 = plt.subplot(222)
ax2.plot(x,-np.sincx,"ro")

ax3 = fig.add_axes((0.125,0.1,0.775,0.45))
ax3.plot(x, np.sincx**2)

plt.show()