PHP警告：参数必须是使用xampp实现可数的数组或对象

Question

我尝试使用xampp运行php程序，但它显示以下错误：

参数必须是实现Countable的数组或对象。

显示错误的代码部分如下所示：

    if (count($this->handles) >= $this->maxHandles) {
        curl_close($resource);
    } else {
        // Remove all callback functions as they can hold onto references
        // and are not cleaned up by curl_reset. Using curl_setopt_array
        // does not work for some reason, so removing each one
        // individually.
        curl_setopt($resource, CURLOPT_HEADERFUNCTION, null);
        curl_setopt($resource, CURLOPT_READFUNCTION, null);
        curl_setopt($resource, CURLOPT_WRITEFUNCTION, null);
        curl_setopt($resource, CURLOPT_PROGRESSFUNCTION, null);
        curl_reset($resource);
        $this->handles[] = $resource;
    }

Answer 1

php中的count（）方法

Warning: count(): Parameter must be an array or an object that implements Countable in … on line..

php8中的该项：

Fatal error: Uncaught TypeError: count(): Argument # 1 ($var) must be of type Countable...

因此，在使用count（）方法检查之前，可以先检查可计数类型是否无效。（例如，根据需要，在此之前使用empty（）方法，或给出空数组值或…）或使用is_数组或is_对象或。。。

7.2.0 count（）现在将对传递给value参数的无效可数类型发出警告。

Answer 2

首先检查如果$this-

if(is_array($this->handles) || is_object($this->handles))
{
        if (count($this->handles) >= $this->maxHandles) {
        curl_close($resource);
    } else {
        // Remove all callback functions as they can hold onto references
        // and are not cleaned up by curl_reset. Using curl_setopt_array
        // does not work for some reason, so removing each one
        // individually.
        curl_setopt($resource, CURLOPT_HEADERFUNCTION, null);
        curl_setopt($resource, CURLOPT_READFUNCTION, null);
        curl_setopt($resource, CURLOPT_WRITEFUNCTION, null);
        curl_setopt($resource, CURLOPT_PROGRESSFUNCTION, null);
        curl_reset($resource);
        $this->handles[] = $resource;
    }
}
else
{
    echo $this->handles." isn't a array or object";
}