人口数据的生成方式

Question

int random_population_result = (rand() % 29000) + 1000;

int random_unemployed_result = (rand() % 1900) + 100;

//number of rows in column
const int colSize = 100;
int col_X[colSize]; //stores X values [population]
int col_Y[colSize]; //stores Y values [unemployed people]
//display table header
cout << "id " << "\t" << "X" << "\t" << "Y" << endl;
for (int i = 0; i < colSize; i++){
    //return value between 1000 and 30 000 of population  
    int random_population_result = (rand() % 30000) + 1000;
    //return value between 100 and 2000 of unemployed people
    int random_unemployed_result = (rand() % 1900) + 100;
    //put values to arrays
    col_X[i] = random_population_result;
    col_Y[i] = random_unemployed_result;
}

问候。

Answer 1

正如user3386109所说，您可能希望有一个真实的数据集。

首先，你想根据人口的结果来创造你的失业率，所以

int random_population_result = (rand() % 30000) + 1000;
int random_unemployed_result = (rand() % (random_population_result-100)) + 100;

然而，如果你想考虑到失业率只能在1%至20%之间，你需要加上以下几点：

int minPercent = 1;
int maxPercent = 20;
int random_population_result = (rand() % 30000) + 1000;
int random_unemployed_result = (rand() % ((maxPercent-minPercent)*random_population_result/100)) + minPercent*random_population_result/100;

int col_X[colSize]; //stores X values [population]
int col_Y[colSize]; //stores Y values [unemployed people]

//display table header
//cout << "id " << "\t" << "X" << "\t" << "Y" << endl;
for (int i = 0; i < colSize; i++){
    //return value between 1000 and 30 000 of population  
    //(ile_liczb_w_przedziale ) + startowa_liczba;
    int minPercent = 1;
    int maxPercent = 20;
    int random_population_result = (rand() % 30000) + 1000;
    int random_unemployed_result = (rand() % ((maxPercent-minPercent)*random_population_result/100)) + minPercent*random_population_result/100;
    //put values to arrays
    col_X[i] = random_population_result;
    col_Y[i] = random_unemployed_result;
}