HTTP请求的正则表达式在某些情况下不起作用

Question

    String somethingPattern = "(.*)?";

    String ipPattern = "(((2[0-4][0-9])|(25[0-5])|(1?[0-9]?[0-9]))\\.((2[0-4][0-9])|(25[0-5])|(1?[0-9]?[0-9]))\\.((2[0-4][0-9])|(25[0-5])|(1?[0-9]?[0-9]))\\.((2[0-4][0-9])|(25[0-5])|(1?[0-9]?[0-9]))|"+somethingPattern+")((:)\\d{3,})?"; // regex for ip varying from 0.0.0.0 to 255.255.255.255 or some string, followed or no by : and a port number 
    String objetoPattern = "([/?a-zA-Z0-9\\.\\-_]+)"; // regex for a linux path to a file, including only letters, numbers and -_.

    String connectionPattern = "(connection:\\s*"+somethingPattern+")?";
    String contentLenPattern = "(content-length:\\s*([0-9]+))?";
    String postmanTokenPattern = "(postman-token:\\s*"+somethingPattern+")?";
    String cacheControlPattern = "(cache-control:\\s*"+somethingPattern+")?";
    String originPattern = "(origin:\\s*"+somethingPattern+")?";
    String userAgentPattern = "(user-agent:\\s*"+somethingPattern+")?";
    String charsetPattern = "(charset="+somethingPattern+")?";
    String contentTypePattern = "(content-type:\\s*"+somethingPattern+";"+charsetPattern+")?";
    String acceptPattern = "(accept:\\s*"+somethingPattern+")?";
    String acceptEncodingPattern = "(accept-encoding:\\s*"+somethingPattern+")?";
    String acceptLanguagePattern = "(accept-language:\\s*"+somethingPattern+")?";


    // (?i) is for the case of coming get, Get, GET... etc...
    String pattern = "^(?i)(get|put|head|post|delete)\\s+?" + objetoPattern + "\\s+?HTTP/1.1\\s+?host:\\s+?" + ipPattern + "\\s+?" + connectionPattern + "\\s+?" + contentLenPattern + "\\s+?" + postmanTokenPattern + "\\s+?" + cacheControlPattern + "\\s+?" + originPattern + "\\s+?" + userAgentPattern + "\\s+?" + contentTypePattern + "\\s+?" + acceptPattern + "\\s+?" + acceptEncodingPattern + "\\s+?" + acceptLanguagePattern + "\\s+?$";

Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(in); // this in is the input string that is the request all joined in a single line string

if(m.find()){
// ......
} else {
  System.out.println("Input didn't match");
}

编辑：处理套接字输入的代码部分：

bufferedReader = new BufferedReader(new InputStreamReader(socket.getInputStream()));

        String in = "";
        while((msgDoSocket = bufferedReader.readLine()) != null){
            try {
                in += msgDoSocket + " ";
                if(msgDoSocket.isEmpty()){
                    processaInput(in); // this calls the part that process regex
                }
            } catch (Exception ex) {
                Logger.getLogger(ServerThread.class.getName()).log(Level.SEVERE, null, ex);
            }
        }

Answer 1

页眉行由换行线分隔，页眉与正文（如果存在）用2个连续的换行线分隔。您应该使用scanner对象，因为它在默认情况下使用换行符分隔标记，这比matcher容易得多。您可以简单地遍历这些行。当您获得这些标题行时，您可以通过“：”对它们进行切片，以形成映射而不是一百万种类型的变量来覆盖所有标题键的可能性。然后您可以简单地检查映射键值以匹配您发送的内容。

此外，您还可以使用Fiddler/Wireshark查看邮递员的原始请求。

这个答案使用reader并按你想要的做。