从GMAIL中提取所有电子邮件，按联系频率分组并排序

Question

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导出到IMAP是否有效（并从那里开始计算）？还是有更聪明的办法

多谢

Answer 1

你有两个选择

1. 您确实可以从IMAP中提取报头（只是报头，不需要完整的消息正文）。
2. 您可以使用Gmail API。如果您想要计算谁给您发送了消息，那么类似这样的方法应该会起作用。

在Python中使用Gmail API的示例代码

# Retrieve a page of threads
threads = gmail_service.users().threads().list(userId='me',fields='threads(id)').execute()

# Print ID for each thread
pp = pprint.PrettyPrinter(depth=5)
if threads['threads']:
  for thread in threads['threads']:
    print 'Thread ID: %s has messages from senders:' % (thread['id'])
    t = gmail_service.users().threads().get(userId='me',id=thread['id'],fields='messages/payload/headers').execute()
    for msg in t['messages']:
      for header_from in [v for v in msg['payload']['headers'] if v['name'] == 'From']:
      # There should be only one, but sometimes From is missing
        from_field_val = header_from['value']
        print from_field_val
        # TODO Extract email address and increment count