如何在JavaFX中找到段落（标签）的终点？

Question

简单的问题，希望有一个简单的解决方案。我在JavaFX应用程序中有一个标签，我希望在段落的末尾有一个按钮。在这一段的结尾，我的意思是好像它是另一个字符。我无法将X和Y设置为特定值，因为段落的长度并不总是相同的，因此该按钮的位置也不总是相同的。

下面，红色是我想要一个按钮的地方。有没有办法通过编程找到这一点？

谢谢

Answer 1

我认为最简单的方法是创建自己的包装方法，根据可用宽度将段落字符串转换为文本（或标签）对象数组，并将这些对象放在流窗格中，最后有一个按钮。我认为您无法轻松检索标签的实际endpoint坐标，因为它是一个覆盖节点边界的矩形。

类似于本问题中的解决方案，将多个Text对象连接在一起：JavaFX：为Text控件设置背景颜色

Answer 2

您可以使用助手方法将长文本拆分为表示单行文本的节点列表。然后，在将文本添加到流程窗格后，只需在末尾添加按钮即可。

看看下面演示的MCVE：

import javafx.application.Application;
import javafx.geometry.Insets;
import javafx.geometry.Pos;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.layout.FlowPane;
import javafx.scene.layout.VBox;
import javafx.scene.text.Text;
import javafx.stage.Stage;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.StringTokenizer;

public class TextFlowSample extends Application {

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage primaryStage) {

        // Simple interface
        VBox root = new VBox(5);
        root.setPadding(new Insets(10));
        root.setAlignment(Pos.CENTER);

        String longText = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nunc nibh sapien, commodo in libero ac, feugiat accumsan odio. Aliquam erat volutpat. Integer accumsan sapien at elit aliquet sagittis. Praesent fermentum nec nunc ultrices mollis. Nam in odio ullamcorper, eleifend quam quis, aliquam sem. Nullam feugiat ex nec elit rutrum blandit. Etiam ut mauris magna. Proin est nunc, viverra quis tempus sed, dictum in lacus.";

        // Create a FlowPane to hold our Text
        FlowPane flowPane = new FlowPane();

        // Now, our button
        Button button = new Button("Click This!");

        // Let's use our custom method to get a list of Text objects to add to the FlowPane
        // Here we can set our max length and determine if we'll allow words to be broken up
        flowPane.getChildren().addAll(getTextsFromString(longText, 75, false));
        flowPane.getChildren().add(button);

        root.getChildren().add(flowPane);

        // Show the Stage
        primaryStage.setWidth(425);
        primaryStage.setHeight(300);
        primaryStage.setScene(new Scene(root));
        primaryStage.show();
    }

    /**
     * Helper method to convert a long String into a List of Text objects
     */
    private List<Text> getTextsFromString(String string, int maxLineLength, boolean breakWords) {

        List<Text> textList = new ArrayList<>();

        // If we are breaking up words, just cut into rows up to the max length
        if (breakWords) {
            int index = 0;
            while (index < string.length()) {
                textList.add(new Text(string.substring(index, Math.min(index + maxLineLength, string.length()))));
                index += maxLineLength;
            }
        } else {

            // First, let's insert linebreaks into the String when max length is reached. The tokenizer here
            // allows us to split the string and keep the spaces, making it easy to loop through later.
            StringTokenizer tokenizer = new StringTokenizer(string, " ", true);
            StringBuilder sb = new StringBuilder();

            int currentLength = 0;
            while (tokenizer.hasMoreTokens()) {
                String word = tokenizer.nextToken();

                // If the next word would exceed our max length, add the new line character
                if (currentLength + word.length() > maxLineLength) {
                    sb.append("\n");
                    currentLength = 0;
                }

                sb.append(word);
                currentLength += word.length();
            }

            // Now we can split the string using the \n as a delimiter
            List<String> rows = Arrays.asList(sb.toString().split("\n"));
            for (String row : rows) {
                textList.add(new Text(row));
            }

        }

        return textList;

    }
}

结果：