如何获取内容，即使我们有错误代码响应

Question

我创建HTTP GET如下所示：

URL obj = new URL(url);
        HttpURLConnection con = (HttpURLConnection) obj.openConnection();
        con.setRequestMethod("GET");

        BufferedReader in = new BufferedReader(
                new InputStreamReader(con.getInputStream()));
        String inputLine;
        StringBuffer response = new StringBuffer();

        while ((inputLine = in.readLine()) != null) {
            response.append(inputLine);
        }

干得好！但是假设服务器返回错误201或错误206。如何得到响应的内容，即使错误代码不是200？我不想使用另一个库，我想使用HttpURLConnection完成此操作

Answer 1

BufferedReader rd = null;

        if (urlConnection.getResponseCode() == 200) {
            rd = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));
        } else {
            rd = new BufferedReader(new InputStreamReader(urlConnection.getErrorStream()));
        }

        StringBuffer result = new StringBuffer();
        String line = "";
        while ((line = rd.readLine()) != null) {
            result.append(line);
        }