如何将单声道转换为通量

Question

使用spring 5，对于reactor，我们有以下需求。

Mono<TheResponseObject> getItemById(String id){
    return webClient.uri('/foo').retrieve().bodyToMono(TheResponseObject)
}

Mono<List<String>> getItemIds(){
    return webClient.uri('/ids').retrieve().bodyToMono(List)
}

Mono<RichResonseObject> getRichResponse(){
    Mono<List> listOfIds = Mono.getItemIds()
    listOfIds.each({ String id ->
        ? << getItemById(id) //<<< how do we convert a list of ids in a Mono to a Flux
    })
    Mono<Object> someOtherMono = getOtherMono()
    return Mono.zip((? as Flux).collectAsList(), someOtherMono).map({
        Tuple2<List, Object> pair ->
        return new RichResonseObject(pair.getT1(), pair.getT2())
    }).cast(RichResonseObject)
}

什么方法可以转换单声道

Answer 1

请找到以下代码：第一次转换Mono

List<String> asList = Arrays.asList("A", "B", "C", "D");
Flux<String> flatMap = Mono.just(asList).flux().flatMap(a-> Flux.fromIterable(a));

或者您可以使用平面地图：

Flux<String> flatMapMany = Mono.just(asList).flatMapMany(x-> Flux.fromIterable(x));

Answer 2

这应该行得通。给定单声道中的字符串列表

  Mono<List<String>> listOfIds;

  Flux<String> idFlux = listOfIds
    .flatMapMany(ids -> Flux.fromArray(ids.toArray(new String [0])));

那就更好了

listOfIds.flatMapMany(Flux::fromIterable)