python解析所有空值的Json

Question

在web2py服务器上使用python我有以下问题。如何循环遍历json以查找所有具有空值（或空字符串）的键并收集这些键以报告丢失的内容：

这是我的json示例。

 {
"version" : 1,
"general" : {
    "scriptFrom" : "",
    "scriptTo" : "1.1.2014",
    "scriptComment" : "dada"
},
"nbworkersDays" : [{
        "days" : ["1", "2"],
        "data" : [{
                "nbWorkersFrom" : 2,
                "nbWorkersTo" : null,
                "timeFrom" : "12:00",
                "timeTo" : ""
            }
        ,{
            "nbWorkersFrom" : 2,
            "nbWorkersTo" : 7,
            "timeFrom" : "9:00",
            "timeTo" : "14:00"
        }
    ]
    }
]}

我想检索一个包含所有键的列表，如果嵌套的话，则不是第一级。二级。missingData=[scriptFrom，nbworkersDays.nbWorkersTo，nbworkersDays.timeTo]

关于如何解决此问题或如何收集所有错误以报告给客户端的任何建议（我有一个使用web2py的Web应用程序）谢谢

Answer 1

您可以使用递归函数来迭代复杂对象的值，同时记住您所在的路径（以便报告）：

#!/usr/bin/env python

# used to parse the json text
import json
with open('json.txt', 'r') as f:
    d = json.load(f)
# define list of what your consider as "missing"
missings = [None, ""]

# recursive function to collect missing paths and alter the aggregator list
# make sure to add cases if needed
def aggregate_missing_paths(aggregator, path, item):
    if isinstance(item, list):
        # check all list items
        map(lambda x: aggregate_missing_paths(aggregator, path, x), item)
    if isinstance(item, dict):
        # check all dict items
        map(lambda kv: aggregate_missing_paths(aggregator, path + '.' + kv[0], kv[1]), item.iteritems())
    if item in missings:
        # alter list to cotain path to missing
        aggregator.append(path)

aggregator = []
aggregate_missing_paths(aggregator, 'root', d)
print aggregator

我使用递归生成器添加了一个没有聚合器的版本：

#!/usr/bin/env python

import json
with open('json.txt', 'r') as f:
    d = json.load(f)
missings = [None, ""]
def generate_missing_paths(path, item):
    if isinstance(item, list):
        for v in item:
            for current_path in generate_missing_paths(path, v):
                yield current_path
    if isinstance(item, dict):
        for k, v in item.iteritems():
            for current_path in generate_missing_paths(path + '.' + k, v):
                yield current_path
    if item in missings:
        yield path

for path in generate_missing_paths('root', d):
    print path