ModelMapper匹配策略：具有参考类型的标准

Question

实体类：

class User{
    private Name name;
    private int age;
    private String email;
    private Date dob;
    private Address address;

  // No Arguments Constructor , All Arguments Constructor , Setters, Getters and toString
}


class Name {
    private String firstName;
    private String lastName;

   // No Arguments Constructor , All Arguments Constructor , Setters, Getters and toString
}

class Address {
    private String houseNo;
    private String street;
    private String city;
    private Integer pincode;

    // No Arguments Constructor , All Arguments Constructor , Setters, Getters and toString
}

DTO：

class UserDTO{
    private String firstName;
    private String lastName;
    private int age;
    private String email;
    private Date dob;
    private String houseNo;
    private String street;
    private String city;
    private Integer pincode;

   // No Arguments Constructor , All Arguments Constructor , Setters, Getters and toString
 }

将实体转换为DTO的代码：

public class ReferenceTypePropertiesMapper {

@Test
public void shouldPopulateAllSimpleProperties(){
    User user = createUser();
    ModelMapper modelMapper = new ModelMapper();
    UserDTO userDTO = modelMapper.map(user,UserDTO.class);

    System.out.println("Source : "+ user);
    System.out.println("Destination : "+ userDTO);
}

private User createUser(){
    Name name = new Name("Siva", "Prasad");
    Address address = new Address("1-93","ABC","HYD",123456);
    return new User(name, 29, "[e-mail]", new Date(), address);
  }
}

输出：

Source : User(name=Name(firstName=Siva, lastName=Prasad), age=29, email=[e-mail], dob=Tue Sep 26 14:38:45 IST 2017, address=Address(houseNo=1-93, street=ABC, city=HYD, pincode=123456))

Destination : UserDTO(firstName=Siva, lastName=Prasad, age=29, email=[e-mail], dob=Tue Sep 26 14:38:45 IST 2017, houseNo=null, street=null, city=null, pincode=null)

我在U中使用了2种引用类型名称和地址ser.java.在为User创建对象时，我也传递了名称和地址详细信息。当我尝试将User对象映射到UserDTO时，名称详细信息被成功映射，但地址详细信息没有被映射。

有谁能帮我理解为什么会这样，或者我错过了什么？

Answer 1

使用匹配策略。松散一切正常。

松散匹配策略允许源属性与目标属性松散匹配，只需要匹配层次结构中的最后一个目标属性。以下规则适用：

• 代币可以任意顺序匹配
• 最后一个目标属性名称必须匹配所有标记
• 最后一个源属性名称必须至少有一个匹配的标记

松散匹配策略非常适合用于属性层次非常不同的源和目标对象模型。它可能会导致检测到更高级别的不明确匹配，但对于已知的对象模型，它可以作为定义映射的快速替代方法。

这样，只需添加一行：

    @Test
    public void shouldPopulateAllSimpleProperties() {
        User user = createUser();
        ModelMapper modelMapper = new ModelMapper();
        modelMapper.getConfiguration().setMatchingStrategy(MatchingStrategies.LOOSE);
        UserDTO userDTO = modelMapper.map(user, UserDTO.class);

        System.out.println("Source : " + user);
        System.out.println("Destination : " + userDTO);
    }

输出：

Source : User{name=Name{firstName='Siva', lastName='Prasad'}, age=29, email='[e-mail]', dob=Wed Oct 18 23:44:25 MSK 2017, address=Address{houseNo='1-93', street='ABC', city='HYD', pincode=123456}}
Destination : UserDTO{firstName='Siva', lastName='Prasad', age=29, email='[e-mail]', dob=Wed Oct 18 23:44:25 MSK 2017, houseNo='1-93', street='ABC', city='HYD', pincode=123456}