使用mockito的JUnit测试用例

Question

我对junit mockito非常陌生，并尝试使用mockito编写junit测试用例。

这是我的方法，我必须为此编写一个jUnit。

public String getAllCookBooks(ChefService chefService, ChefApi chefApi) {
    JSONObject cookBooks = null;
    cookBooks = new JSONObject();
    JSONArray array = null;
    array = new JSONArray();

    try {
        if (null != chefService.listCookbookVersions()) {
            LOG.debug(SuccessCode.COOKBOOK_DETAILS_RETRIEVED_SUCCCESS
                    .getSuccessCode()
                    + "::"
                    + SuccessCode.COOKBOOK_DETAILS_RETRIEVED_SUCCCESS
                            .getMessage());
            for (CookbookVersion cookbookVersion : chefService
                    .listCookbookVersions()) {

                JSONObject cookBooksDetails = new JSONObject();

                cookBooksDetails.put("cookbook_name",
                        cookbookVersion.getCookbookName());
                cookBooksDetails.put("cookbook_version",
                        cookbookVersion.getVersion());

                cookBooksDetails.put("name", cookbookVersion.getName());
                array.put(cookBooksDetails);
            }
        } else {
            LOG.info("no cookbook present..."
                    + ErrorCode.COOKBOOK_LIST_EMPTY_ERROR.getErrorCode()
                    + " : "
                    + ErrorCode.COOKBOOK_LIST_EMPTY_ERROR.getMessage());
            cookBooks.put("error",
                    ErrorCode.COOKBOOK_LIST_EMPTY_ERROR.getMessage());
        }
        cookBooks.put("chef_cookbooks", array);
    } catch (JSONException e) {
        LOG.warn("JSON Exception "
                + ErrorCode.JSON_PARSE_ERROR.getErrorCode() + " "
                + ErrorCode.JSON_PARSE_ERROR.getMessage());
    }

    LOG.debug("cookbooks: " + cookBooks.toString());
    LOG.info("Ended getAllCookBooks method");
    return cookBooks.toString();
}

ChefService和ChefApi传递的方法参数来自第三方api

这里是呼叫chefService。listCookbookVersions（）将返回CookBookVersion类类型的迭代器，如Iterable

请帮忙。




Answer 1

你要做的（很可能）是：

ChefService chefService = mock(ChefService.class); // create the mock
when(chefService.listCookbookVersions()).thenReturn(aListOfValues); // establish what would be returned on method call, in this case 'aListOfValues'

// you could do the same for chefApi

String result = getAllCookbooks(chefService, chefApi); // call you method

//assert something on the result

Answer 2

你不能传递任何信息。您明确地告诉框架，当调用这个特定调用时，将返回一些内容。

ChefService chefServiceMock = mock(ChefService.class);
// some reasonable, expected entry value
List<CookbookVersion> cookbookVersions = ...; 
when(chefServiceMock.listCookbookVersions()).thenReturn(cookbookVersions);
// You're not actually using the API object, so you can pass in null.
// It'd be wiser to remove it altogether.
String actual = testObject.getAllCookBooks(chefServiceMock, null);

完成后，您需要确保它已被调用，因此您需要验证调用。

// later
verify(chefServiceMock).listCookbookVersions();

然后，确保您验证了实际结果。我见过只验证模拟工作的测试，但实际生成的数据是垃圾。

确保它是您希望从API输入列表中接收的数据。