spring.jpa.hibernate.ddl auto=验证或更新返回beans.factory.BeanCreationException

Question

在第一次测试运行期间，如果我使用validate或update而不是spring.jpa.hibernate.ddl auto=create drop，则会发生以下错误（请参阅错误消息）。使用create drop时，应用程序启动并工作时只会出现一个错误：“error o.h.e.j.e.i.jdbconvironmentimpl-无法从数据库java.sql.SQLException:数值溢出”

如果你能帮助我，我将非常高兴。不幸的是，以前的论坛报名没有成功。

应用程序

Oracle设置

spring.datasource.url=jdbc:oracle:thin:@//example:1521/example
spring.datasource.username=User
spring.datasource.password=user
spring.datasource.driver-class-name=oracle.jdbc.OracleDriver
spring.datasource.continueOnError: true
spring.batch.initialize-schema=always

HikariCP设置

spring.datasource.hikari.connection-timeout=60000
spring.datasource.hikari.maximum-pool-size=5

登录中

logging.pattern.console=%d{yyyy-MM-dd HH:mm:ss} %-5level %logger{36} - %msg%n
logging.level.org.hibernate.SQL=DEBUG

JPA/Hibernate

spring.jpa.show-sql=true
spring.jpa.generate-ddl=true
spring.jpa.hibernate.ddl-auto=validate
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.Oracle12cDialect

Pom.xml

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.2.6.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>
    <groupId>com.example</groupId>
    <artifactId>OracleDatabaseConnection</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <name>OracleDatabaseConnection</name>
    <description>Demo project for Spring Boot</description>

    <properties>
        <java.version>1.8</java.version>
    </properties>

    <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-data-jpa</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-jdbc</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>
        <dependency>
            <groupId>com.oracle</groupId>
            <artifactId>ojdbc8</artifactId>
            <version>12.2.0.1</version>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
            <exclusions>
                <exclusion>
                    <groupId>org.junit.vintage</groupId>
                    <artifactId>junit-vintage-engine</artifactId>
                </exclusion>
            </exclusions>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>

</project>

import java.util.Set;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="AMP_MS_USER") 
public class User {
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="USER_SEQUENCE")
      @SequenceGenerator(sequenceName = "MS_USER_SEQUENCE", allocationSize = 1, name = "USER_SEQUENCE")
    @Column(name="id_calcuser")
    private Long id_calcuser;
    

    @Column(name="username")
    private String username;
    
    @Column(name="password")
    private String password;

    public User() {
        
    }

    public User(String username, String password) {
        super();
        this.username = username;
        this.password = password;
    }

    public Long getId_calcuser() {
        return id_calcuser;
    }

    public void setId_calcuser(Long id_calcuser) {
        this.id_calcuser = id_calcuser;
    }

    

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

}

SQL开发人员中的序列

-- Create sequence 
create sequence MS_USER_SEQUENCE
minvalue 1
maxvalue 9999999999999999999999999999
start with 1
increment by 1
cache 20;

错误消息

2020-04-20 13:53:11 ERROR o.h.e.j.e.i.JdbcEnvironmentImpl - Could not fetch the SequenceInformation from the database
java.sql.SQLException: Numeric Overflow
    at oracle.jdbc.driver.NumberCommonAccessor.throwOverflow(NumberCommonAccessor.java:4136)
    at oracle.jdbc.driver.NumberCommonAccessor.getLong(NumberCommonAccessor.java:591)
    at oracle.jdbc.driver.GeneratedStatement.getLong(GeneratedStatement.java:206)
    at oracle.jdbc.driver.GeneratedScrollableResultSet.getLong(GeneratedScrollableResultSet.java:259)
    at oracle.jdbc.driver.GeneratedResultSet.getLong(GeneratedResultSet.java:558)
    at com.zaxxer.hikari.pool.HikariProxyResultSet.getLong(HikariProxyResultSet.java)
    at org.hibernate.tool.schema.extract.internal.SequenceInformationExtractorLegacyImpl.resultSetMinValue(SequenceInformationExtractorLegacyImpl.java:134)
    at org.hibernate.tool.schema.extract.internal.SequenceInformationExtractorLegacyImpl.extractMetadata(SequenceInformationExtractorLegacyImpl.java:60)
    at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentImpl.sequenceInformationList(JdbcEnvironmentImpl.java:403)
    at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentImpl.<init>(JdbcEnvironmentImpl.java:268)
    at org.hibernate.engine.jdbc.env.internal.JdbcEnvironmentInitiator.initiateService(JdbcEnvironmentInitiator.java:114)

Answer 1

您要么需要更改序列的最大值，要么更改ID的数据类型。

Your sequence:     9,999,999,999,999,999,999,999,999,999
Max positive long: 9,223,372,036,854,775,807

Answer 2

您的问题在于最小值-这在异常SequenceInformationExtractorLegacyImpl.ResultSetInvalue

它意味着定义了一个降序序列，该序列具有必须重置的高（默认）最小值。

请注意，这不是您使用的序列所必需的，而是您的用户可以访问的序列。请参阅相应的Hibernate错误中的更多详细信息

1）找出它是哪个序列

select SEQUENCE_OWNER, SEQUENCE_NAME, MIN_VALUE from ALL_SEQUENCES order by min_value;

您可能会在顶部看到MIN_VALUE-999999999999999999999999999

现在你有两种可能的解决方法——要么2）要么3）

2） 调整最小值的大小

提供propper所有者和序列名称，并将值设置为允许的最小长值

ALTER SEQUENCE ooo.seq_xxxxx 
  MINVALUE   -9223372036854775808;

3）撤销对序列的访问

如果Hibernate simple未使用该序列，请从连接用户处撤销它，它将从所有_序列中消失，不再造成任何伤害。

提供propper序列和连接用户名

 revoke  select on  ooo.seq_xxxxx from connection_user; 

您可能需要致电DBA来执行此操作。