如何使用node和mongodb查找？

Question

以下数据存储在我的收藏中

[
{ "_id" : ObjectId("53d9feff55d6b4dd1171dd9e"),"name":"John", "rank":1, "year":1998 ,"class":"a" ,"total":"1128" },
{ "_id" : ObjectId("feff553d95d6b4dd19e171dd"),"name":"Sherif", "rank":1, "year":1999 ,"class":"b" ,"total":"1163"},
{ "_id" : ObjectId("9fef53dd6b4dd1171f55dd9e"),"name":"shravan", "rank":1, "year":2000 ,"class":"b" ,"total":"1113"},
{ "_id" : ObjectId("117153d9fef6b4dddd9ef55d"),"name":"aneesh", "rank":1, "year":2001 ,"class":"d" ,"total":"1145"},
{ "_id" : ObjectId("dd9e53feff55d6b4dd1171d9"),"name":"abdul", "rank":1, "year":1997 ,"class":"a" ,"total":"1100"},
]

我为find和[{“name”：“John”，“rank”：1，“year”：1998}，{“name”：“Sherif”，“rank”：1，“year”：1999}]编写了api这是我从req获得的数据。我在这里提到的身体是一个疑问

router.post('/users',function(req,res){
  var query =[{ "name":"John", "rank":1, "year":1998 },{ "name":"Sherif", "rank":1, "year":1999 }]
  User.find(query, function(err, result) {
    if (err) throw err;
    console.log(result);
    res.json(result)

  });

我希望这个res.json应该只返回这两个文档

[
{ "_id" : ObjectId("53d9feff55d6b4dd1171dd9e"),"name":"John", "rank":1, "year":1998 ,"class":"a" ,"total":"1128" },
{ "_id" : ObjectId("feff553d95d6b4dd19e171dd"),"name":"Sherif", "rank":1, "year":1999 ,"class":"b" ,"total":"1163"}]

在mongoDB我们可以这样写

db.users.find({rank:1, name:{$in:["John","Sherif"]}, year:{$in:[1998,1999]}})

我想要nodejs中的解决方案，因为根据请求我们需要找到帮助我

Answer 1

虽然有几个人回答了，但我相信完整的方法是：

router.post('/users',function(req, res, next) {
    // req.body = [{ "name":"John", "rank":1, "year":1998 },{ "name":"Sherif", "rank":1, "year":1999 }]

    // mapping users to each array
    const query = { $or: req.body };
    // execute query
    User.find(query, function(err, result) {
        if (err) next(err);
        console.log(result);
        res.json(result);
    });
});

Answer 2

您的查找查询应该如下所示：

db.collection.find({rank:1, name:{$in:["John","Sherif"]}, year:{$in:[1998,1999]}})

结果将是：

/* 1 */
{
"_id" : ObjectId("53d9feff55d6b4dd1171dd9e"),
"name" : "John",
"rank" : 1,
"year" : 1998,
"class" : "a",
"total" : "1128"
}

/* 2 */
{
"_id" : ObjectId("feff553d95d6b4dd19e171dd"),
"name" : "Sherif",
"rank" : 1,
"year" : 1999,
"class" : "b",
"total" : "1163"
}

Answer 3

尝试使用猫鼬$或运算符

var query = {
  $or : [
    {
      "name":"John", 
      "rank":1,
      "year":1998 
    },
    {
      "name":"Sherif",
      "rank":1, "year":1999 
    }
  ]
}