Java 11：使用收集器将list转换为treemap

Question

我有一张这样的单子

List<String> customList = Arrays.asList(
   "5000  Buruli ulcer is an infectious disease",
   "6000  characterized by the development",
   "7000  of painless open wounds.",
   "8000  The disease largely occurs in",
   "10000  sub-Saharan Africa and Australia."
);

"5000", ["Buruli", "ulcer", "is", "an", "infectious", "disease"]
"6000", ["characterized", "by", "the", "development"]
// etc

TreeMap<String, List<String[]>> collect = customList.stream()
      .map(s -> s.split("  ", 2))
      .collect(Collectors
         .groupingBy(a -> a[0], TreeMap::new, Collectors.mapping(a -> a[1].split(" "), Collectors.toList())));

null

Answer 1

您希望使用LinkedHashMap来保留原始顺序。因此您的代码应该如下所示：

Map<String, List<String>> collect = customList.stream()
    .map(s -> s.split(" +"))
    .collect(Collectors.toMap(a -> a[0], a -> Arrays.asList(a)
        .subList(1, a.length), (a, b) -> a, LinkedHashMap::new));

如果您的键不是唯一的，您可以使用分组收集器如下所示(collectors.flatmappingrequires Java 9+):

collect = customList.stream()
    .map(s -> Arrays.asList(s.split(" +")))
    .collect(Collectors.groupingBy(l -> l.get(0), 
        LinkedHashMap::new, 
        Collectors.flatMapping(l -> l.stream().skip(1), Collectors.toList())));