从img标签中提取src属性

Question

<div class="someClass">
    <a href="href">
        <img alt="some" src="some"/>
    </a>
</div>

我想从图像（即img）标签中提取源（即src）属性，我使用bs4，我不能使用a.attrs['src']来获取src，但是我可以获取href。我该怎么办？

Answer 1

这里有一个解决方案，如果img标签没有src属性，它不会触发KeyError：

from urllib.request import urlopen
from bs4 import BeautifulSoup

site = "[insert name of the site]"
html = urlopen(site)
bs = BeautifulSoup(html, 'html.parser')

images = bs.find_all('img')
for img in images:
    if img.has_attr('src'):
        print(img['src'])

Answer 2

链接没有属性src，您必须以实际img标记为目标。

import bs4

html = """<div class="someClass">
    <a href="href">
        <img alt="some" src="some"/>
    </a>
</div>"""

soup = bs4.BeautifulSoup(html, "html.parser")

# this will return src attrib from img tag that is inside 'a' tag
soup.a.img['src']

>>> 'some'

# if you have more then one 'a' tag
for a in soup.find_all('a'):
    if a.img:
        print(a.img['src'])

>>> 'some'

Answer 3

您可以使用BeautifulSoup来提取html img标记的src属性。在我的示例中，htmlText包含img标记本身，但这也可以与urllib2一起用于URL。

对于URL

from BeautifulSoup import BeautifulSoup as BSHTML
import urllib2
page = urllib2.urlopen('http://www.youtube.com/')
soup = BSHTML(page)
images = soup.findAll('img')
for image in images:
    #print image source
    print(image['src'])
    #print alternate text
    print(image['alt'])

对于带有img标签的文本

from BeautifulSoup import BeautifulSoup as BSHTML
htmlText = """<img src="https://src1.com/" <img src="https://src2.com/" /> """
soup = BSHTML(htmlText)
images = soup.findAll('img')
for image in images:
    print(image['src'])

Python 3:2022-02-02更新

from bs4 import BeautifulSoup as BSHTML
import urllib

page = urllib.request.urlopen('https://github.com/abushoeb/emotag')
soup = BSHTML(page)
images = soup.findAll('img')

for image in images:
    #print image source
    print(image['src'])
    #print alternate text
    print(image['alt'])

如果需要，安装模块

# python 3
pip install beautifulsoup4
pip install urllib3