如何分配ajax对象到属性？[重复]

Question

class ClassList
{
    private _workDate: string = null;
    private _fromTime: string = null;
    private _toTime: string = null;
    private _roomId: string = null;
    private _slotId: string = null;

    constructor() {

    }

    public get WorkDate(): string {
        return this._workDate;
    }

    public set WorkDate(value: string) {
        this._workDate = value;
    }

    public get FromTime(): string {
        return this._fromTime;
    }

    public set FromTime(value: string) {
        this._fromTime = value;
    }


    public get ToTime(): string {
        return this._toTime;
    }

    public set ToTime(value: string) {
        this._toTime = value;
    }


    public get RoomId(): string {
        return this._roomId;
    }

    public set RoomId(value: string) {
        this._roomId = value;
    }


    public get SlotId(): string {
        return this._slotId;
    }

    public set SlotId(value: string) {
        this._slotId = value;
    }
}


 $(data).each(function (i, v) {
                v=> ClassList;
                console.log(v);
 }

我已经创建了一个类get set，但是调试显示v有一个对象类型，如何将对象分配到属性中？有什么想法吗？

Answer 1

您需要调用传递数据搬迁对象（ajax返回值）的类的构造函数，并将DTO的属性分配给类实例的成员。

您可以在类构造函数中使用lodash extend之类的工具来实现这一点，这样就不需要复制单个属性。