从员工时钟中查找开始日期和结束日期

Question

我试图找出明星日期和结束日期的员工时钟。以下是我所掌握的数据示例。

PersonID  EventTime                       ActivityCode
1         2019-07-29 00:03:03.000         7
1         2019-07-29 00:09:41.000         0
1         2019-07-29 00:01:07.000         7
1         2019-07-29 00:01:19.000         0

需要输出：

PersonID  EventTime                   EndTime                           ActivityCode
1         2019-07-29 00:03:03.000     2019-07-29 00:09:41.000            7
1         2019-07-29 00:09:41.000     2019-07-29 00:01:07.000            0
1         2019-07-29 00:01:07.000      2019-07-29 00:01:19.000           7
1         2019-07-29 00:01:19.000                                        0

我必须根据eventtime和activitycode找到此人的开始日期和结束日期。开始日期将是事件时间列，我必须从行中下一个事件时间的同一列计算结束日期。

我曾尝试在T-SQL中使用lead函数，但它并没有给出我想要的结果。

select personid, activitycode, eventtime as starttime
    , (lead(eventtime) over (order by personid)) as endtime 
from ActivityTable

如果有人知道如何处理这个问题，我会非常感激。

Answer 1

像这样试试。。

  CREATE TABLE #T 
 (
PersonID INT
,EventTime DATETIME
,ActivityCode INT
)



INSERT INTO #T(
PersonID
,EventTime
,ActivityCode
)
SELECT
PersonID
,EventTime
,ActivityCode
FROM
(VALUES ( 1,'2019-07-29 00:03:03.000', 7)
        ,(1,'2019-07-29 00:09:41.000', 0)
        ,(1,'2019-07-29 00:13:07.000', 7)
        ,(1,'2019-07-29 00:13:19.000', 0)) AS T (PersonID,EventTime,ActivityCode)

SELECT  PersonID,EventTime,ActivityCode,
    (SELECT MIN(EventTime) FROM #T T2 WHERE T1.PersonID = T2.PersonID AND 
    T1.EventTime < T2.EventTime)
  FROM  #T T1

Answer 2

在您的示例中，您的输出看起来有点奇怪，因为事件时间似乎发生在结束时间之后。如果您正在查找时间顺序，并且希望得到如下结果集：

那么xQbert的评论是正确的。您只需通过在订单中添加EventTime即可。请参见下面的示例代码。

CREATE TABLE #T (
    PersonID INT
    ,EventTime DATETIME
    ,ActivityCode INT
)

INSERT INTO #T(
    PersonID
    ,EventTime
    ,ActivityCode
)
SELECT
    PersonID
    ,EventTime
    ,ActivityCode
FROM
    (VALUES ( 1,'2019-07-29 00:03:03.000', 7)
            ,(1,'2019-07-29 00:09:41.000', 0)
            ,(1,'2019-07-29 00:01:07.000', 7)
            ,(1,'2019-07-29 00:01:19.000', 0)) AS T (PersonID,EventTime,ActivityCode)


SELECT
    PersonID
    ,ActivityCode
    ,EventTime AS starttime
    ,(LEAD(EventTime) OVER (ORDER BY PersonID, EventTime DESC)) AS endtime
FROM
    #T;

Answer 3

我想你的活动时间应该是13点而不是01点

示例

Declare @YourTable Table ([PersonID] varchar(50),[EventTime] datetime,[ActivityCode] int)  Insert Into @YourTable Values 
 (1,'2019-07-29 00:03:03.000',7)
,(1,'2019-07-29 00:09:41.000',0)
,(1,'2019-07-29 00:13:07.000',7)  << changed to 13
,(1,'2019-07-29 00:13:19.000',0)  << changed to 13

Select PersonID
      ,EventTime 
      ,EndTime= lead([EventTime],1) over (partition by [PersonID] order by [EventTime])
      ,ActivityCode
 From @YourTable
 Order by EventTime

退换商品

PersonID    EventTime                 EndTime                   ActivityCode
1           2019-07-29 00:03:03.000   2019-07-29 00:09:41.000   7
1           2019-07-29 00:09:41.000   2019-07-29 00:13:07.000   0
1           2019-07-29 00:13:07.000   2019-07-29 00:13:19.000   7
1           2019-07-29 00:13:19.000   NULL                      0