假装客户端无法将响应json转换为Java对象，因为开头的字符无效

Question

我创建了一个假客户机EmployeeServiceClient.java，如下所示

@FeignClient(name = "employeeclient", url = "https://internel.omnesys.org")
public interface EmployeeServiceClient {
    @RequestMapping(method = RequestMethod.GET, value = "/v1/employees")
    List<EmployeeDetails> getEmployeeDetails();
}

Employeedetails.java

public class EmployeeDetails {
  private Employee employee;
  private String empId;
  // getters and setters
}

Employee.java

public class Employee {
  private String name;
  private String firstName;
  private String lastName;
  private String city;
  // getters and setters
}

服务https://internel.omnesys.org/v1/employees（这是一个由不同团队管理的intranet REST服务）为我提供了如下所示的响应寿命

)}]',
[{"employee":{"name":"Emp1","firstName":"firstName1","lastName":"lastName1","city":"city1"},"empId":"empId123"},{"employee":{"name":"Emp2","firstName":"firstName2","lastName":"lastName2","city":"city2"},"empId":"empId456"}]

Answer 1

我看到三种选择：

>

使用自定义配置自定义客户机，并提供自己的解码器来处理疯狂的响应；）扩展ResponseEntityDecoder并添加特殊的响应处理。

将方法签名更改为返回Feign.Response并自行处理：

@FeignClient(name = "employeeclient", url = "https://internel.omnesys.org")
public interface EmployeeServiceClient {
  @RequestMapping(method = RequestMethod.GET, value = "/v1/employees")
  feign.Response getEmployeeDetails();
}

请注意：为2。和3，根本不会有错误处理，您应该注意这一点

如果不选择第一个选项，还可以考虑添加适配器，以隐藏解析和异常处理，并确保当前方法签名。