我无法提供ViewModel

Question

当我在@ContributesAndroidInjector(modules=[MainFragmentBuilderModule::Class，LoginViewModelProviderModule::Class])中包含LoginViewModelProviderModule时，我无法使用LoginViewModelProviderModule提供LoginViewModel，但当我在ActivityBuilderModule类的@Module注释中包含它时，它可以工作。

BaseApplicationComponent

@Suppress("unused")
@Singleton
@Component(
    modules = [AndroidInjectionModule::class,
        ActivityBuilderModule::class,
        ViewModelFactoryModule::class]
)
interface BaseApplicationComponent : AndroidInjector<BaseApplicationClass> {

    @Component.Builder
    interface Builder {

        @BindsInstance
        fun application(application: Application): Builder

        fun build(): BaseApplicationComponent
    }
}

ActivityBuilderModule

@Module
abstract class ActivityBuilderModule {

    @LoginScope
    @ContributesAndroidInjector(modules = [MainFragmentBuilderModule::class, LoginViewModelProviderModule::class])
    abstract fun contributeMainActivity(): MainActivity
}

@Module
abstract class MainFragmentBuilderModule {

    @ContributesAndroidInjector
    abstract fun contributesLoginFragment(): LoginFragment
}

LoginViewModelProviderModule

@Suppress("unused")
@Module
abstract class LoginViewModelProviderModule {
    @Binds
    @IntoMap
    @ViewModelKey(LoginViewModel::class)
    abstract fun bindLoginViewModel(viewModel: LoginViewModel): ViewModel
}

ViewModelFactoryModule

@Module
abstract class ViewModelFactoryModule {

    @Binds
    abstract fun bindViewModelFactory(viewModelProviderFactory: ViewModelProviderFactory): ViewModelProvider.Factory
}

ViewModelProviderFactory

@Singleton
class ViewModelProviderFactory @Inject constructor(
    private val creators: Map<Class<out ViewModel>, @JvmSuppressWildcards Provider<ViewModel>>
) : ViewModelProvider.Factory {
    override fun <T : ViewModel> create(modelClass: Class<T>): T {
        val creator = creators[modelClass] ?: creators.entries.firstOrNull {
            modelClass.isAssignableFrom(it.key)
        }?.value ?: throw IllegalArgumentException("unknown model class $modelClass") as Throwable
        try {
            @Suppress("UNCHECKED_CAST")
            return creator.get() as T
        } catch (e: Exception) {
            throw RuntimeException(e)
        }
    }
}

@Scope
@MustBeDocumented
@Retention(AnnotationRetention.RUNTIME)
annotation class LoginScope 

@MustBeDocumented
@Target(
    AnnotationTarget.FUNCTION,
    AnnotationTarget.PROPERTY_GETTER,
    AnnotationTarget.PROPERTY_SETTER
)
@Retention(AnnotationRetention.RUNTIME)
@MapKey
annotation class ViewModelKey(val value: KClass<out ViewModel>)

Answer 1

只能在应用程序中创建viewmodel的模块bind all。您可以在我的示例应用程序中看到详细信息：sample-moviedb-app

BaseApplicationComponent：

@Suppress("unused")
@Singleton
@Component(
    modules = [AndroidInjectionModule::class,
        ActivityBuilderModule::class,
        ViewModelFactoryModule::class,
        ViewModelModule::class]

)
interface BaseApplicationComponent : AndroidInjector<BaseApplicationClass> {
    @Component.Builder
    interface Builder {

        @BindsInstance
        fun application(application: Application): Builder

        fun build(): BaseApplicationComponent
    }
}

ViewModelModule：

@Suppress("unused")
@Module
abstract class ViewModelProviderModule {
    @Binds
    @IntoMap
    @ViewModelKey(LoginViewModel::class)
    abstract fun bindLoginViewModel(viewModel: LoginViewModel): ViewModel

//other viewmodels in application
   @Binds
   abstract fun bindViewModelFactory(viewModelProviderFactory:ViewModelProviderFactory): ViewModelProvider.Factory
}

主模块：

@Module
class MainModule {
    @MainActivityScope
    @Provides
    fun provideViewModel(mainActivity: MainActivity, viewModelFactory: ViewModelProviderFactory) =
        ViewModelProviders.of(mainActivity, viewModelFactory).get(LoginViewModel::class.java)
}

class LoginViewModel @Inject constructor(
) : ViewModel() {

}