Spring Boot身份验证中的堆栈溢出

Question

我试图在Spring Boot中创建一个简单的角色登录。

我有一个用户类：

package com.codecool.domain;


import lombok.Data;
import lombok.extern.slf4j.Slf4j;

import javax.persistence.*;
import java.util.Set;

@Data
@Entity
@Table(name="users")
@Slf4j
public class User {

@Id
@Column(name="user_id", unique = true)
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Long id;

@Column(name="email")
private String email;

@Column(name="password")
private String password;

@ManyToMany(fetch=FetchType.EAGER)
@JoinTable(name="user_role", joinColumns =         @JoinColumn(name="user_id"), inverseJoinColumns = @JoinColumn(name="role_id"))
private Set<Role> roles;

private User(){}

public User(String email, String password, Set<Role> roles) {
    this.email = email;
    this.password = password;
    this.roles = roles;
}

package com.codecool.domain;


import lombok.Data;
import lombok.extern.slf4j.Slf4j;

import javax.persistence.*;
import java.util.Set;

@Data
@Entity
@Table(name="role")
@Slf4j
public class Role {

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    private Long id;

    private String name;

    @ManyToMany(mappedBy = "roles", fetch=FetchType.EAGER)
    private Set<User> users;

    private Role(){}

    public Role(String name){
        this.name = name;
    }
}

每当我尝试通过login.html登录时，我就会进入一个无限循环，出现以下错误消息：

知道我错过了什么吗？

Answer 1

当您想要返回RestController中的对象时，对象序列化到json.spring，使用jackson序列化。为了解决这个问题，您想要jsonignore user或roles，例如ignore users in role.java

@Data
@Entity
@Table(name="role")
@Slf4j
public class Role {

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    private Long id;

    private String name;

    @ManyToMany(mappedBy = "roles", fetch=FetchType.EAGER)
    @JsonIgnore
    private Set<User> users;

    private Role(){}

    public Role(String name){
        this.name = name;
    }
}