需要只显示基本身份验证的spring security java配置示例

Question

我当前的java安全配置如下所示：

@Configuration
@EnableWebSecurity
public class RootConfig extends WebSecurityConfigurerAdapter {

@Override
protected void registerAuthentication(AuthenticationManagerBuilder auth) throws Exception
{
auth.inMemoryAuthentication()
    .withUser("tester").password("passwd").roles("USER");
}

@Override
protected void configure(HttpSecurity http) throws Exception {
     http
     .authorizeUrls()
         .anyRequest().authenticated()
         .and()
     .httpBasic();       
  }
}

当我使用浏览器执行GET请求时，我会得到一个错误403。我希望看到一个浏览器弹出窗口，询问我用户名/密码。可能有什么问题？

Answer 1

使用Spring Security 4.2.3以及之前的版本，您可以简单地使用此配置：

@Configuration
@EnableWebSecurity
public class CommonWebSecurityConfig extends WebSecurityConfigurerAdapter {

   @Override
   protected void configure(final HttpSecurity http) throws Exception {
     http
        .authorizeRequests()
           .anyRequest().authenticated()
           .and()
        .httpBasic();
  }
  @Autowired
  public void dlcmlUserDetails(final AuthenticationManagerBuilder auth) throws Exception {
      auth.inMemoryAuthentication()
          .withUser("tom").password("111").roles("USER");
  }
}

Answer 2

更新：这在Spring Security 3.2.0中已修复。RC1

这是安全Java配置中的一个错误，将在下一个版本中解决。我已经创建了SEC-2198来跟踪它。现在，一个解决方法是使用以下内容：

@Bean
public BasicAuthenticationEntryPoint entryPoint() {
    BasicAuthenticationEntryPoint basicAuthEntryPoint = new BasicAuthenticationEntryPoint();
    basicAuthEntryPoint.setRealmName("My Realm");
    return basicAuthEntryPoint;
}

@Override
protected void configure(HttpSecurity http) throws Exception {

    http
        .exceptionHandling()
            .authenticationEntryPoint(entryPoint())
            .and()
        .authorizeUrls()
            .anyRequest().authenticated()
            .and()
        .httpBasic();       
}

PS：感谢您尝试Spring Security Java配置！保持反馈：）