SQL服务器行冷却[复制]

Question

我似乎是一个简单的任务，但我需要SQL专家的一些帮助。

联系人的数量可以从1人到30人不等，我希望每个cust\u ref的所有电话号码都排在一行。

我怎么能这样做？？

Answer 1

通过使用交叉应用、连接时序分析和联合，我们可以得到上述要求

declare @tableA table (RefId int,Phone varchar(10))
insert into @tableA (RefId,Phone)values (10000,'030123456'),(100123,060123445)

Declare @tableB table (CustID  INT,RefId INT,Phone varchar(10)))
insert into @tableB (CustID,RefId,Phone)values 
(1,10000,'030245789'),
(2,10000,'030245889'),
(1,100123,'060245789'),
(2,100123,'060243389'),
(3,100123,'060289389')

; with CTE AS (
select A.RefId,A.Phone As Phone from @tableA A 
UNION 
select B.RefId,B.Phone As Phone from @tableB B )

 select * from (
 Select RefId,
 val,
 COL + CAST(ROW_NUMBER()OVER(PARTITION BY RefId ORDER BY RefId) AS VARCHAR(1))RN  
    FROM CTE 
CROSS APPLY (VALUES ('Phone',Phone))CS(Col,val))T
PIVOT (MAX(VAL) FOR RN IN ([Phone1],[Phone2],[Phone3],[Phone4]))P 

Answer 2

这是一个没有动态sql的解决方案，请尝试：

declare @contacts table(cust_ref int,phone varchar(100));
insert into @contacts values(10000,'ph10000a'),(10000,'ph10000b'),(10000,'ph10000c')
                           ,(10001,'ph10001a'),(10001,'ph10001b'),(10001,'ph10001c') 
                           ,(10002,'ph10002a'),(10002,'ph10002b');

SELECT p.*
FROM
( 
    SELECT 'phone'+REPLACE(STR(ROW_NUMBER() OVER(PARTITION BY cust_ref ORDER BY phone),2),' ','0') AS inx,*
    FROM @contacts    
) AS tbl
PIVOT
(
    MIN(phone) FOR inx IN(phone01,phone02,phone03,phone04) --type more...
) AS p