如何在Python中正确比较2个JSON请求响应字符串

Question

我想比较2个Python响应字符串并打印出差异，这是我现在的代码：

导入请求导入json导入时间

getFirst=requests.get（"https://api-mainnet.magiceden.dev/v2/collections?offset=0

true： get=requests.get（"https://api-mainnet.magiceden.dev/v2/collections?offset=0

if get.status_code == 200:
    print("ok")
if dataPretty != data:
    for item in data:
        if str(item) not in liveRN:
            send = 1
            print(f"Found difference: {item}")

            symbol = item['symbol']
            img = item['image']
            name = item['name']
            description = item['description']

            print(symbol)
            print(img)
            print(name)
                         
        else:
            print("Didnt find")
else:
    print("No change")

time.sleep(15)

我只想在两个重复不匹配时打印项目，但现在它可以打印我想要的项目，即使字符串确实匹配。

我试图看到添加另一个if条件，如果2请求响应匹配，它不会做任何事情，只是通过，但那不起作用

Answer 1

您可以使用set来查找字典的项目是否已更改。我使用了另一个问题的比较代码，但这在某种程度上是您可以用于解决问题的

import requests 
import time

def dict_compare(d1, d2):
    d1_keys = set(d1.keys())
    d2_keys = set(d2.keys())
    shared_keys = d1_keys.intersection(d2_keys)
    added = d1_keys - d2_keys
    removed = d2_keys - d1_keys
    modified = {o : (d1[o], d2[o]) for o in shared_keys if d1[o] != d2[o]}
    same = set(o for o in shared_keys if d1[o] == d2[o])
    return added, removed, modified, same

first = requests.get("https://api-mainnet.magiceden.dev/v2/collections?offset=0&limit=1").json()[0]

while True: 
    get_second = requests.get("https://api-mainnet.magiceden.dev/v2/collections?offset=0&limit=1")

    if get_second.status_code == 200:
        print("ok")

    second = get_second.json()[0]
    added, removed, modified, same = dict_compare(first, second)

    if len(added) > 0 or len(modified) > 0  or len(removed) > 0:
        print("added: ", added)
        print("modified: ", modified)
        print("removed: ", removed)
    else:
        print("No change")
        
    time.sleep(15)