LazyInitializationException：未能懒洋洋地初始化角色集合：FQPropretyName,无法初始化代理-没有会话

Question

    @Test
    public void testFindByRegionIdEquals() {
        Region region = regionService.findByRegionIdEquals(1L);
        Region expectedRegion = new Region(1L, "Europe");
        assertThat(region).isNotNull().isEqualTo(expectedRegion);
        assertThat(region.getCountries()).isNotEmpty().doesNotContainNull().size().isEqualTo(8);
    }

    org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: zikzakjack.domain.Region.countries, could not initialize proxy - no Session
    at org.hibernate.collection.internal.AbstractPersistentCollection.throwLazyInitializationException(AbstractPersistentCollection.java:587)
    at org.hibernate.collection.internal.AbstractPersistentCollection.withTemporarySessionIfNeeded(AbstractPersistentCollection.java:204)
    at org.hibernate.collection.internal.AbstractPersistentCollection.readSize(AbstractPersistentCollection.java:148)
    at org.hibernate.collection.internal.PersistentSet.isEmpty(PersistentSet.java:149)
    at org.assertj.core.util.IterableUtil.isNullOrEmpty(IterableUtil.java:35)
    at org.assertj.core.internal.Iterables.assertNotEmpty(Iterables.java:152)
    at org.assertj.core.api.AbstractIterableAssert.isNotEmpty(AbstractIterableAssert.java:145)
    at zikzakjack.service.RegionServiceTests.testFindByRegionIdEquals(RegionServiceTests.java:68)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)

@Data
@Entity
@Table(name = "COUNTRIES")
public class Country implements Serializable, Comparable<Country> {

    private static final long serialVersionUID = 1L;

    @Id
    @Column(name = "COUNTRY_ID")
    private String countryId;

    @Column(name = "COUNTRY_NAME")
    private String countryName;

    @ManyToOne
    @JoinColumn(name = "REGION_ID")
    private Region region;

    public Country() {

    }

    public Country(String countryId, String countryName, Region region) {
        super();
        this.countryId = countryId;
        this.countryName = countryName;
        this.region = region;
    }

}

*非拥有实体OneToMany与mappedBy*

@Data
@Entity
@Table(name = "REGIONS")
public class Region implements Serializable, Comparable<Region> {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "REGION_ID")
    private Long regionId;

    @Column(name = "REGION_NAME")
    private String regionName;

    @OneToMany(mappedBy = "region", fetch = FetchType.LAZY)
    private Set<Country> countries = new HashSet<Country>();

    public Region() {
    }

    public Region(Long regionId, String regionName) {
        this.regionId = regionId;
        this.regionName = regionName;
    }

    public Region(String regionName) {
        this.regionName = regionName;
    }

    public void addCountry(Country country) {
        countries.add(country);
        country.setRegion(this);
    }
}

Answer 1

嗯，我从这个帖子中找到了答案https://stackoverflow.com/a/38690930/5266568

在application.properties中添加下面的配置解决了这个问题：

spring.jpa.properties.hibernate.enable_lazy_load_no_trans=true

另一个对我有效的解决方案，但请注意，我仍然需要更多地了解它是如何真正解决这个问题的

    @Test
    @Transactional
    public void testFindByRegionIdEquals() {
        Region region = regionService.findByRegionIdEquals(1L);
        Region expectedRegion = new Region(1L, "Europe");
        assertThat(region).isNotNull().isEqualTo(expectedRegion);
        assertThat(region.getCountries()).isNotEmpty().doesNotContainNull().size().isEqualTo(8);
    }