如何在Spock中模拟类的单个方法？

Question

我在我的类中有一个方法，如下所示，我试图测试它：

class SomeHelper { 
    ByteArrayOutputStream fooBar (Request request) {
       ByteArrayOutputStream baos = someParser.parseData(getRequestFileInputStream(request.filename))
       return baos
    }
    InputStream getRequestFileInputStream(String filename) {
      //return intputStream of object from S3
    }
....
}

在上面，GetRequestFileInputStream是一个方法，它将文件名作为参数。它从AWS S3中获取该文件的inputstream。在测试Spock的Foobar方法时，我希望为GetRequestFileInputStream方法提供一个模拟，因为我不想使用类中的这个方法的实现，因为它转到了另一个bucket名称。

class SomeHelperSpec extends Specification{
    //this is the implementation of getRequestFileInputStream I want to use while testing
    InputStream getObjectFromS3(String objectName) {
            def env = System.getenv()
            AwsClientBuilder.EndpointConfiguration endpoint = new AwsClientBuilder.EndpointConfiguration(env["endpoint_url"], env["region_name"])
            AmazonS3ClientBuilder builder = AmazonS3ClientBuilder.standard()
            builder.setEndpointConfiguration(endpoint)
            builder.setCredentials(new AWSStaticCredentialsProvider(new BasicAWSCredentials(env["ACCESS_KEY"], env["SECRET_KEY"])))
            AmazonS3 s3 = builder.build()
            return s3.getObject("testbucket", objectName).getObjectContent()

    }

    def "test fooBar" () {
      given: 
         someHelper = new SomeHelper()
         someHelper.getRequestFileInputStream(_) >> getObjectFromS3(fileName)
         someHelper.someParser = Mock(SomeParser) {
           ....
         }
         Request requestInstance = new Request()
         request.filename = fileName
         request.fileType = fileType
      expect:
         someHelper.fooBar(requestInstance).getText == returnVal

      where:
         fileType | fileName      | returnVal    
         "PDF"    | "somepdf.pdf" | "somereturnval"
    }
}

Answer 1

您可以使用实际对象，但使用重写的方法：

given:
    someHelper = new SomeHelper() {
         @Override
         InputStream getRequestFileInputStream(String filename) {
             return getObjectFromS3(fileName)
         }
    }