如果字符串与正则表达式不完全匹配，我怎么能忽略字符串？

Question

例如，我想忽略这个字符串123 456 78912，但是正则表达式匹配了前三个字符，所以它返回true。有没有办法在不创建新正则表达式的情况下做到这一点？

正则表达式还必须匹配以下内容：

0（123）456-789-ABcd

0 (123) 456

(123) 234 345-456

1111111111111

1 123 123 123 123

123个

123-（456）

123 (456) 789

（电话）

（123）

private boolean checkValidity(String number){
    // Check value using regex and set value to field only if sastify these rules:
    //
    //   Phone number is split using space or dash
    //   Prefix may have +
    //   1st/2nd group have (), maximum only one grp
    //   grp contains number/upper/lowercase, at least two symbols in length
    //   1st grp may have one symbol in length

    Pattern pattern = Pattern.compile("^\\+?\\d{0,100}(\\w+[ -]+)*([ -]+\\(\\w+\\)[ -]+|[ -]+\\(\\w+\\)$|\\(\\w+\\)[ -]+|\\(\\w+\\)$){0,2}([ -]?\\w)*");
    Matcher matcher = pattern.matcher(number);
    boolean matchFound = matcher.find();

    if(matchFound){
        return true;
    }
    System.out.println("Wrong number format!");
    return false;
}

Answer 1

使用matcher.group（）检查原始值和匹配值。等于

private boolean checkValidity(String number){
        //check value using regex and set value to field only if sastify these rules:
        //Phone number is split using space or dash
        //Prefix may have +
        //1st/2nd group have (), max only 1 grp
        //grp contains number/upper/lowercase, at least 2 symbols in length
        //1st grp may have 1 symbol in length

        Pattern pattern = Pattern.compile("(^\\+?\\d{0,100}(\\w+[ -]+)*([ -]+\\(\\w+\\)[ -]+|[ -]+\\(\\w+\\)$|\\(\\w+\\)[ -]+|\\(\\w+\\)$){0,1}([ -]?\\w{2,100})*)");
        Matcher matcher = pattern.matcher(number);
        boolean matchFound = matcher.find();
        //System.out.println(matcher.group());
        if(matchFound && matcher.group().equals(number)){
            return true;
        }
        System.out.println("Wrong number format!");
        return false;
    }