SpringBoot：如何通过RestTemplate HttpMethod Get发送对象？

Question

class User {

  String firstName;
  String lastName;

}

User dto=new User("abc","xyz");

// Is this possible ?

HttpEntity<User> entity=new HttpEntity<>(dto);
restTemplate.exchange(url, HttpMethod.GET, entity, Object.class);

// Is this possible ?

@GetMapping("/url")
Object getData(@RequestBody User user){

}

HashMap<String,String> map=new HashMap<>();
map.put("name", "abc");
HttpEntity<User> entity=new HttpEntity<>(map);

restTemplate.exchange(url, HttpMethod.GET, entity, Object.class);

微服务2

// Is this possible ?

@GetMapping("/url")
Object getData(@RequestParam HashMap<String,String> user){

   sysout(user) // Null

}

Answer 1

需要使用HTTP post方法发送主体，get可以有请求参数。

 ResponseEntity<UserResponse> responseEntity = restTemplate.exchange(
                url,
                HttpMethod.POST,
                requestEntity,
                UserResponse.class
        );

可以像下面这样构建请求实体。

//setting up the request headers
        HttpHeaders requestHeaders = new HttpHeaders();
        requestHeaders.setContentType(MediaType.APPLICATION_JSON);    

        //setting up the request body
        User user = new User();
        user.setName("Sample User");
        user.setUsername("user1");
        user.setPassword("pass123");

        //request entity is created with request body and headers
        HttpEntity<User> requestEntity = new HttpEntity<>(user, requestHeaders);

要了解更多详细信息，请通过此链接。