java.io。IOException：服务器返回了URL的HTTP响应代码：400：

Question

我正在做一个GET请求，这段代码适用于我们所有现有的测试，对于一个新endpoint，它给出了400个错误。我可以在《邮差》中很好地达到终点。conn.getErrorStream（）不打印任何内容。代码似乎在url.openConnection处失败（没有引发异常）。如果我在那行之后执行conn.getResponseCode（），它返回400。我想可能它不喜欢查询中的管道字符，而是通过URLEncoder对其进行编码。encode（resourceContext）以及URLEncoder。encode（baseUrl resourceContext）没有帮助，最终引发了MalformedURLException。以下是我想要点击的endpoint（匿名）：https://usqa0003d.usa.company.com:17462/positions/1535000400000/CUR/USA|415 | 415 | CUST | GL53I7TPYBYM |匹配

当我将调试器连接到服务器时，我想什么都不发生，所以请求永远不会到达服务器。我进入openConnection，这导致了一个充满var5、var6等的兔子洞。我切换到HttpsURLConnection，但那里也没有骰子。还有其他建议吗？

URL url = new URL(baseUrl + resourceContext);
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod(requestType);
        if(messageLibraryJson) {
            conn.setRequestProperty("Content-Type", "application/json;class=true");
            conn.setRequestProperty("Accept", "application/json;class=true");
        } else {
            conn.setRequestProperty("Content-Type", "application/json");
            conn.setRequestProperty("Accept", "application/json");
        }

        String userpass = username + ":" + password;
        String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());
        conn.setRequestProperty("Authorization", basicAuth);

        if(requestType.equals("POST")) {
            OutputStream os = conn.getOutputStream();
            os.write(requestJson.getBytes());
            os.flush();
        }

        if (conn.getResponseCode() != HttpURLConnection.HTTP_OK) {
            logger.error("ERROR in REST CLIENT");
            logger.error("URL = " + baseUrl + resourceContext);
            logger.error("Request = " + requestJson);
            throw new RuntimeException("Failed : HTTP error code : "
                    + conn.getResponseCode());
        }

        BufferedReader br = new BufferedReader(new InputStreamReader(
                (conn.getInputStream())));

Answer 1

事实上，是“|”字符引起了麻烦。如果我执行以下操作：

        String urlString = (baseUrl + resourceContext).replace("|", "%7C");
        URL url = new URL(urlString);
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();

它起作用了。生成以下URL字符串：https://usqa0003d.usa.company.com:17462/positions/1535000400000/CUR/USA|415 | 415 | CUST | GL53I7TPYBYM |匹配

但是，当我这样做时：

String enc = baseUrl + URLEncoder.encode(resourceContext);

我得到：https://clqa0003d.usa.company.com:17462/positions/1535000400000/CUR/USA|415|415|CUST|GL53I7TPYBYM|匹配

“/”被替换为“/”（除了管道字符之外），并且由于某种原因导致了问题。作为参考，endpoint实际上是这样定义的：

@RequestMapping(value = "/{param1}/{param2}/{param3:.*}", method = RequestMethod.GET)

类级endpoint（如何称为？？？）为：

@RequestMapping(value = "/positions",
    produces = {"application/vnd.cme.cdo+json", "application/json;class=true", "application/x-protobuf", "application/x-protobuf-text"},
    consumes = {"application/vnd.cme.cdo+json", "application/json;class=true", "application/x-protobuf", "application/x-protobuf-text"})
public class PositionController implements IPositionController {

有人能评论一下为什么将“/”转换为“/”会引起麻烦吗？