如何打印从今天开始的下3个日期？[副本]

Question

我有一个代码可以告诉输入位置的天气。我想做一个选项打印未来3天的天气，我需要发送到我的功能3个日期（与循环），每次不同的日期，我如何发送从今天起的未来3天的日期？

#This is my function
def weather(city, date): 

#This is the part where I send it from the main to the function:
city = 'Paris'
while(i < 4):
    i += 1
    weather(city.lower(), dd/mm/yyyy)# Here instead of "dd/mm/yyyy" I need to send every time the next date from today.

Answer 1

使用dateTime.timeDelta(Days=1)将日期增加1，如下所示，您可以将此日期传递给函数

import datetime
curr_date = datetime.datetime.now()

for i in range(4):
    curr_date += datetime.timedelta(days=1)
    print(curr_date)
#2019-04-19 22:01:29.503352
#2019-04-20 22:01:29.503352
#2019-04-21 22:01:29.503352
#2019-04-22 22:01:29.503352