使用Jackson Java反序列化具有无值属性的XML元素

Question

<video src="https://google.com/sample.mp4">
    <param>s</param>
    <param>Y</param>
    <param>Z</param>
</video>

import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;

import java.util.ArrayList;
import java.util.List;

public class Video {
    @JacksonXmlProperty(isAttribute = true)
    private String src;

    @JacksonXmlElementWrapper(localName = "param", useWrapping = false)
    private List<String> param = new ArrayList<>();

    public String getSrc() {
        return src;
    }

    public List<String> getParam() {
        return param;
    }

    public void setParam(List<String> param) {
        this.param = param;
    }
}

{
    "src": "https://google.com/sample.mp4",
    "param": [
        "Z"
    ]
}

{
    "src": "https://google.com/sample.mp4",
    "param": [
        "s",
        "Y",
        "Z"
    ]
}

ObjectMapper mapper = new ObjectMapper(new XmlFactory());
mapper.enable(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
Video video = mapper.readValue(s, Video.class);
System.out.println(new ObjectMapper(new JsonFactory()).writeValueAsString(video));

有人能帮我把它弄好吗。谢谢你。

Answer 1

我使用了以下代码,

XmlMapper mapper = new XmlMapper();
    mapper.enable(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY);
    Video video = mapper.readValue(s, Video.class);
    System.out.println(new ObjectMapper(new JsonFactory()).writeValueAsString(video));

XMLMapper是来自于程序包com.fasterxml.jackson.dataformat.xml.XMLMapper

希望对你有帮助。