如何忽略字母大小写？[副本]

Question

所以，我试着做一个简单的带有开关的菜单。

还要注意：我使用旧版本的Java和NetBeans8.2作为IDE。（因为我的学院一直坚持不使用新的。可能是因为他们还没有课本。），所以可能新的语法不起作用。

我的代码：

import java.util.Scanner;

public class NewClass2 {


      public static void main(String[] args) {


      Scanner input = new Scanner (System.in);
      char milk;
       int s, h, price;
       h = 0;
       price = 0;
       String type, size;
      System.out.println("NutMart");
      System.out.println("Milk selections:\n A. Milk A \n\t 1. Regular ($10) \n\t 2. Medium ($20) \n\t 3. Large ($30)");
      System.out.println(" B. Milk B \n\t 1. Regular ($15) \n\t 2. Medium ($30) \n\t 3. Large ($45)");
       System.out.println(" C. Milk C \n\t 1. Regular ($20) \n\t 2. Medium ($40) \n\t 3. Large ($60)");

      System.out.println("Insert Milk Type: ");
      milk = input.next().charAt(0);

      switch(milk){
              case 'a':
              type = "Milk A";
              h = 10;
              break;
              case 'b':
              type = "Milk B";
              h = 15;
              break;
              case 'c':
              type = "Milk C";
              h = 20;
              break;
              case 'A':
             type = "Milk A";
              h = 10;
              break;
              case 'B':
              type = "Milk B";
              h = 15;
              break;
              case 'C':
              type = "Milk C";
              h = 20;
              break;
              default: 
                  System.out.println("Invalid!");
                  System.out.println("Please select the correct choice: ");
      milk = input.next().charAt(0);
                     break;
      }
      System.out.println("Select the size: ");
    while (!input .hasNextInt()) input .next();
    s = input.nextInt();

      switch(s){
          case 1:
              size = "Regular";
              price = h * 1;
              break;
              case 2:
              size = "Medium";
              price = h * 2;
              break;
              case 3:
              size = "Large";
              price = h * 3;
              break;
               default: 
                  System.out.println("Invalid");
                   System.out.println("Please select the correct choice: ");
    while (!input .hasNextInt()) input .next();
    s = input.nextInt();
                     break;
      }
          System.out.println("Individual Price: $" + price);
        System.out.println("Please insert the quantity: ");
    while (!input .hasNextInt()) input .next();
    int quantity = input.nextInt();

    int total = price * quantity;


      System.out.println("Your total will be $" + total );

      }
}

Answer 1

注意，在这种情况下，转换为一致的情况是最好的是达到您的目标。但是，当switch语句中不同的输入有不同的结果时，可以对case构造执行以下操作。

      case 'a':
      case 'A:
              type = "Milk A";
              h = 10;
              break;
      ...

这种情况将简单地归结为是提供了“A”还是“A”。