laravel中razorpay响应后缺少路线所需的参数

Question

我试图重定向到某个路由：url以捕获我的付款，我必须传递付款id和金额以从控制器捕获，但路由会产生如下错误

提前谢谢

我犯的错误

ErrorException (E_ERROR)
  Missing required parameters for [Route: razorpay.standard.success] [URI: razorpay/standard/success/{rzpId}/{amount}]. (View: /home/valpuia/projects/bagisto/packages/Vaube/Razorpay/src/Resources/views/standard-redirect.blade.php)

我的路线

Route::prefix('razorpay/standard')->group(function () {
    Route::get('/success/{rzpId}/{amount}', 'RazorPayController@success')->name('razorpay.standard.success');
}

控制器

public function success($rzpId, $amt)
{
    dd($rzpId);
}

刀身razorpay完成后的php

"handler": function (response){
            // alert(response.razorpay_payment_id);
            if (typeof response.razorpay_payment_id == 'undefined' || response.razorpay_payment_id < 1) {
                redirect_url = '{{ route('razorpay.standard.cancel') }}';
            } else {
                redirect_url = '{{ route('razorpay.standard.success', [ "rzp_id" => 'response.razorpay_payment_id', "amount" => '$total_amount * 100']) }}';
            }
            location.href = redirect_url;
        },




Answer 1

我想你的参数名有误。

请更换

<代码>"rzp_id"=

与

“rzpId”=

并尝试

Answer 2

不能在PHP中使用javascript变量

尝试以下解决方案：

Route::prefix('razorpay/standard')->group(function () {
    Route::get('/success/{rzpId?}/{amount?}', 'RazorPayController@success')->name('razorpay.standard.success');
}

然后把路线改成

"handler": function (response){
            // alert(response.razorpay_payment_id);
            if (typeof response.razorpay_payment_id == 'undefined' || response.razorpay_payment_id < 1) {
                redirect_url = '{{ route('razorpay.standard.cancel') }}';
            } else {
                redirect_url = '{{ route("razorpay.standard.success")}}/'+response.razorpay_payment_id+'/'+'{{$total_amount * 100}}';
            }
            location.href = redirect_url;
        },