PowerShell将日期输入Switch语句

Question

我试图在PowerShell中创建一个switch语句，以根据dayofweek和get-date运行不同的代码块，我认为它已经工作了，直到通过设置一个特定的日期进行测试，我发现代码并不像预期的那样工作。

在完美世界中，脚本将在周一运行。我的目标是以这些格式输出三个变量2/02/2015 1:00 am2015-02-02 Monday，基本上是从星期一到下星期一增加一天。

问题来自于我试图预期脚本在周一以外的另一天运行。因此，我想使用(Get-Date).adddays($I)来输出正确的日期，但是当我以后尝试使用Get-Date设置日期时，返回的日期是不正确的。

当我开始使用$var=(Get-date-year 2015-month 02-day 04).DayOfWeek进行测试以设置特定的日期时，switch语句没有输出正确的日期。

下面是switch语句：

#$var = (get-date).DayOfWeek
$var = [DayOfWeek]::Sunday
#$var = (get-date -Year 2015 -Month 02 -Day 04).DayOfWeek
Switch ($var){
([DayOfWeek] 'Monday'){
for ($i = 1; $i -le 7; $i++){
 $d = ((Get-Date).AddDays($i))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Monday
([DayOfWeek] 'Tuesday'){
$i= 5,-1,0,1,2,3,4
foreach ($day in $i){
 $d = ((Get-Date).AddDays($day))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Tuesday
([DayOfWeek] 'Wednesday'){
$i= 5,-1,0,1,2,3,4
foreach ($day in $i){
 $d = ((Get-Date).AddDays($day))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Wednesday
([DayOfWeek] 'Thursday'){
$i= 4,-1,0,1,2,3,4
foreach ($day in $i){
 $d = ((Get-Date).AddDays($day))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Thursday
([DayOfWeek] 'Friday'){
$i= 5,-1,0,1,2,3,4
foreach ($day in $i){
 $d = ((Get-Date).AddDays($day))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Friday
([DayOfWeek] 'Saturday'){
$i= 5,-1,0,1,2,3,4
foreach ($day in $i){
 $d = ((Get-Date).AddDays($day))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Saturday
([DayOfWeek] 'Sunday'){
$i= 1,-1,0,1,2,3,4
foreach ($day in $i){
 $d = ((Get-Date).AddDays($day))
 $d2 = ($d.ToString("M/dd/yyyy") + " 1:00 AM")
 $d3 = ($d.ToString("yyyy-MM-dd"))
 $d4 = (($d).DayOfWeek).ToString().ToUpper()
"$d2 $d3 $d4"}#End For
}#End Sunday
}#End Switch

然后，可以通过在get-date代理函数中设置get-date来使脚本中的每个get-date实例返回所需的任意日期。

Answer 1

这可能会有帮助。没有开关，只是数学。您可以将格式字符串更改为您喜欢的任何格式。只需更改“yyyy-mm-dd dddd hh：mm tt”。请参见自定义日期和时间格式字符串，以了解如何准确地获得所需的输出。

function get-nextweek ([System.DateTime]$p1)
{
    #Set the time to 01:00
    $p1 = [DateTime]($p1.Date + "01:00")
    # + 1 week + 2 days (Tuesday) - Current day of week (0 based) % 7 + 0..6
    0..6 | %{
             #get number of days till Monday
             $d = (8-$p1.DayOfWeek)%7+$_
             #Add 7 if today is Monday to get next week
             if($d -eq 0){$d=7}
             #Output the days as a custom string
             $out = $p1.AddDays($d)
             "$($out.ToString('MM/dd/yyyy HH:mm tt yyyy-MM-dd')) $($out.DayOfWeek.ToString().ToUpper())"
    }
}

产出：

C:\ > get-nextweek '01-29-2015'
02/02/2015 01:00 AM 2015-02-02 MONDAY
02/03/2015 01:00 AM 2015-02-03 TUESDAY
02/04/2015 01:00 AM 2015-02-04 WEDNESDAY
02/05/2015 01:00 AM 2015-02-05 THURSDAY
02/06/2015 01:00 AM 2015-02-06 FRIDAY
02/07/2015 01:00 AM 2015-02-07 SATURDAY
02/08/2015 01:00 AM 2015-02-08 SUNDAY