编写程序输出一组按词典顺序排列的字符串。我三个字就越界了？[副本]

Question

我目前正在下面的程序上工作。它需要3个输入单词，并按词典编撰顺序输出它们。我觉得我得到了一个越界的异常，因为我刚刚输入了一个错误的数字，但我找不到它。下面是代码：

class LexicoOrder {
      public static void main(String[] args) {
         Scanner in = new Scanner(System.in);
                
        System.out.println("Enter a word: ");
        String firstword = in.nextLine();
        
        System.out.println("Enter another word: ");
        String secondword = in.nextLine();
        
        System.out.println("Enter one more word: ");
        String thirdword = in.nextLine();
         
    
        String[] words = {firstword, secondword, thirdword};
    
        for(int i = 0; i < 3; ++i) {
          for (int j = i + 1; j < 4; ++j) {
              
            if (words[i].compareTo(words[j]) > 0) { // receive error here. Out of bounds
    

              String temp = words[i];
              words[i] = words[j];
              words[j] = temp;
            }
          }
        }
    
        System.out.println("In lexicographical order:");
        
        for(int i = 0; i < 3; i++) {
          System.out.println(words[i]);
        }
      }
    }

Answer 1

 for(int i = 0; i < 3; ++i) {
      for (int j = i + 1; j < 4; ++j) {
          
        if (words[i].compareTo(words[j]) > 0) 

问题是当j变成3时，它会达到点，所以单词[3]是越界的。改为使用以下内容：

 for(int i = 0; i < 3; ++i) {
      for (int j = i + 1; j < 3; ++j) {
          
        if (words[i].compareTo(words[j]) > 0) 

永远记住索引是从0开始的，所以你的索引是0,1,2而不是3。