当输入错误的详细信息时，改造响应为空

Question

在登录表单中-

在邮递员-

这是我的活动--

RetrofitClient.instance.userLogin(email, password)
  .enqueue(object : Callback<LoginResponse> {
override fun onFailure(call: Call<LoginResponse>, t: Throwable) {
   Log.d("res", "" + t)
            }

 override fun onResponse(
   call: Call<LoginResponse>,
       response: Response<LoginResponse>
        ) {
            var res = response

            Log.d("response check ", "" + response.body()?.status.toString())
            if (res.body()?.status==200) {
  SharedPrefManager.getInstance(applicationContext)
                 .saveUser(response.body()?.data!!)

             val intent = Intent(applicationContext, HomeActivity::class.java)
             intent.flags = Intent.FLAG_ACTIVITY_NEW_TASK or Intent.FLAG_ACTIVITY_CLEAR_TASK
             Toast.makeText(
                            applicationContext,
                            res.body()?.message,
                            Toast.LENGTH_LONG
                        ).show()
                        startActivity(intent)
                        finish()
              } else {
                //Log.d("res", "" +  res.body()?.status.toString())
                Toast.makeText(
                applicationContext, (res.body()?.status.toString())
                            ,
                Toast.LENGTH_LONG
                 ).show()
           }

谢谢提前帮助将不胜感激

Answer 1

最后我得到了答案:

      val jObjError =JSONObject(response.errorBody()!!.string())
                            Toast.makeText(
                                applicationContext,
                                jObjError.getString("message")+jObjError.getString("user_msg"),
                                Toast.LENGTH_LONG
                            ).show()
                        } catch (e: Exception) {
                           Toast.makeText(applicationContext, e.message, Toast.LENGTH_LONG).show()
                            Log.e("errorrr",e.message)
                        }

Answer 2

用这个，

res.code()

而不是，

res.body()?.status