使用where子句连接Spring Data JPA中的两个表实体

Question

我一直在为下面的问题寻找答案，到目前为止什么也没有找到。

@Entity
@Data
@NoArgsConstructor
@AllArgsConstructor
@Table(name = "ROLE")
@Where(clause = "RECORD_STATUS = 'A'")
@SQLDelete(sql = "UPDATE ROLE SET RECORD_STATUS = 'D' where OBJID = ?")
public class Role extends BaseEntity implements Serializable {

   private String roleDescription;
   private String roleName;



   @JoinTable(
        name = "ROLE_PRIVILEGE",
        joinColumns = @JoinColumn(
                name = "roleOid"
        ),
        inverseJoinColumns = @JoinColumn(
                name = "privilegeOid"
        )
    )
    @Where(clause = "RECORD_STATUS = 'A'")
    @ManyToMany(fetch = FetchType.EAGER)
    List<Privilege> privileges;
}

@Entity
@Data
@NoArgsConstructor
@AllArgsConstructor
@Table(name = "PRIVILEGE")
@Where(clause = "RECORD_STATUS = 'A'")
@SQLDelete(sql = "UPDATE PRIVILEGE SET RECORD_STATUS = 'D' where OBJID = ?")
public class Privilege extends BaseEntity implements Serializable {

   private String description;
   private String privilegeName;



}

@Entity
@Data
@NoArgsConstructor
@AllArgsConstructor
@Table(name = "ROLE_PRIVILEGE")
@Where(clause = "RECORD_STATUS = 'A'")
@SQLDelete(sql = "UPDATE ROLE_PRIVILEGE SET RECORD_STATUS = 'D' where OBJID 
= ?")
public class RolePrivilege extends BaseEntity implements Serializable {

   private String roleOid;
   private String privilegeOid;

}

select
 privileges0_.role_oid as role_oid8_23_0_,
 privileges0_.privilege_oid as privileg7_23_0_,
 privilege1_.objid as objid1_21_1_,
 privilege1_.creation_date as creation2_21_1_,
 privilege1_.last_change_date as last_cha3_21_1_,
 privilege1_.luc as luc4_21_1_,
 privilege1_.record_status as record_s5_21_1_,
 privilege1_.user_created as user_cre6_21_1_,
 privilege1_.description as descript7_21_1_,
 privilege1_.privilege_name as privileg8_21_1_
from
 role_privilege privileges0_
 inner join
  privilege privilege1_
   on privileges0_.privilege_oid=privilege1_.objid
where
(
  privilege1_.RECORD_STATUS = 'A'
)
and privileges0_.role_oid=?

Answer 1

我真的不知道我是怎么错过的，但找到了解决办法。

@WhereJoinTable(clause = "RECORD_STATUS = 'A' ")

JPA@jointable（带有额外连接条件）