类类型的反映

Question

public void DoWork<TClass>(int time)
{
     IJobDetail job = JobBuilder.Create<TClass>()
                .WithIdentity("job1", "group1")
                .Build();
}

`The type TClass cannot be used as type parameter T in the generic type or method quartz.jobbuilder.create<T>().  There is now boxing conversion or type parameter conversion from tclass to quartz.ijob`

石英创建方法

// Summary:
    //     Create a JobBuilder with which to define a Quartz.IJobDetail, and set the
    //     class name of the job to be executed.
    //
    // Returns:
    //     a new JobBuilder
    public static JobBuilder Create<T>() where T : IJob;

Answer 1

您可能正在寻找一个泛型函数--这允许您的函数指定一个类型参数：

public void DoWork<TClass>(int time)
    where TClass : quartz.ijob
{
    IJobDetail job = JobBuilder.Create<TClass>()
        .WithIdentity("job1", "group1")
        .Build();
}

编辑

您还可以对类型参数设置一个限制，这似乎是这里所需要的。使用语法其中TClass:quartz.ijob。

DoWork<SomeClassType>(123);

public void DoWork<TClass>(int time, TClass instance)
    where TClass : quartz.ijob

var myInstance = new SomeClassType();  // SomeClassType must inherit quartz.ijob
DoWork(123, myInstance);

function SomethingOrOther(object instance)
{
    DoWork(123, instance);   // will not compile, as the compiler doesn't know the type of "instance"
}