Hibernate本机查询：无效列名错误SQL-17006

Question

package com.abc.def.model;

import javax.persistence.Column;
import javax.persistence.Id;
import javax.persistence.Entity;
import javax.persistence.Embeddable;
import javax.persistence.IdClass;
import java.util.Date;
import java.io.Serializable;



@NamedNativeQuery(name="getMetadata",query="
                  select a.name alias1,a.fullname alias2,
                         b.name alias3,b.age alias4,
                         c.height alias5,c.something alias6,
                         d.otherthing alias7
                  from lame_table_name a,
                       lame_table_name_2 b
                  where a.id = b.id
                     and b.id = c.id 
                     and c.id = d.id 
                     and d.id = :namedparameter
                  order by a.index,b.index
               ",
            resultClass=MetadataModel.class)


  @Entity
  @IdClass(SomeIdClass.class)

  public class MetadataModel{

  @Id @Column("alias1")
  private Type alias1property;

  @Id @Column("alias2")
  private Type2 alias2property;

  @Column("alias3")
  private Type3 alias3property;

  //getters and setters
  }

  @Embeddable
  class SomeIdClass implements Serializable{

  //serialVersionUID line

  @Id @Column("alias1")
  private Type alias1property;

  @Id @Column("alias2")
  private Type2 alias2property;

  //getter and setters
  }

package com.abc.def.model;

import javax.persistence.Column;
import javax.persistence.Id;
import javax.persistence.Entity;
import javax.persistence.Embeddable;
import javax.persistence.IdClass;
import java.util.Date;
import java.io.Serializable;
//other imports for the SqlResultSetMapping



@NamedNativeQuery(name="getMetadata",query="
                  select a.name alias1,a.fullname alias2,
                         b.name alias3,b.age alias4,
                         c.height alias5,c.something alias6,
                         d.otherthing alias7
                  from lame_table_name a,
                       lame_table_name_2 b
                  where a.id = b.id
                     and b.id = c.id 
                     and c.id = d.id 
                     and d.id = :namedparameter
                  order by a.index,b.index
               ",
            resultSetMapping="metaDataMapping")


@SqlResultSetMapping(name="metaDataMapping",
              entities=@EntityResult(entityClass=MetadataModel.class,
                fields = {@FieldResult(name="alias1Property",column="alias1")
                           //so on
                      }

                 )
            )

  @Entity
  @IdClass(SomeIdClass.class)

  public class MetadataModel{


  private Type alias1property;


  private Type2 alias2property;


  private Type3 alias3property;

  //getters and setters
  }

  //composite class, exactly as above

Answer 1

我们应该在Oracle的选择列表中有所有的表列。如果我们只保留几列。例如，表Employee有列FirstName、LastName、EmpId和如果有query like。

session.createSQLQuery("Select FirstName from Employee");

上面的查询不起作用。它将抛出无效列错误异常。因此，最好将所有列放在Oracle的Select子句中。

礼貌：一个答案谢谢，拉杰什。