如果字符串包含连字符，则使用regex验证第二个名称

Question

/**
     *   Determines if the string is valid and returns result code
     *
     *   @param fio                  string to validate
     *   @return                     1 - valid second name, name, patronymic; 2 - valid second name, name; 0 - invalid string
     */
    public static int Validate(String fio) {
        Pattern pattern;
        Matcher matcher;
        try {
            pattern = Pattern.compile("([A-Z])[a-z]+ ([A-Z])[a-z]+ ([A-Z])[a-z]+"); //second name; name; patronymic
            matcher = pattern.matcher(fio);
            if (matcher.matches()) return 1;

            pattern = Pattern.compile("([A-Z])[a-z]+ ([A-Z])[a-z]+"); //second name; name
            matcher = pattern.matcher(fio);
            if (matcher.matches()) return 2;

        } catch (PatternSyntaxException ex1) {
            System.out.println("String is incorrect!");
        }
        return 0;
    }

你能告诉我如何改变我的regex字符串模式来验证带有连字符的第二个名称吗？

Answer 1

您可以使用

public static int Validate(String fio) {
    //second name; name; patronymic
    if (fio.matches("\\p{Lu}\\p{Ll}+(?:-\\p{Lu}\\p{Ll}+)* \\p{Lu}\\p{Ll}+ \\p{Lu}\\p{Ll}+")) {
        return 1;
    }
    //second name; name
    if (fio.matches("\\p{Lu}\\p{Ll}+(?:-\\p{Lu}\\p{Ll}+)* \\p{Lu}\\p{Ll}+")) {
        return 2;
    }
    return 0;
}

\p{Lu}\p{Ll}+（？:-\p{Lu}\p{Ll}+)*regex匹配

• \p{Lu}-大写Unicode字母
• \p{Ll}+-1+小写Unicode字母
• （？：-\p{Lu}\p{Ll}+)*-零次或多次重复
  • --连字符
  • \p{Lu}-大写Unicode字母
  • \p{Ll}+-1+小写Unicode字母

  System.out.println(Validate("Стриженов Анатолий Иванович"));
  // => 1
  System.out.println(Validate("Стриженов Анатолий"));
  // => 2
  System.out.println(Validate("Стриженов-Бродский Анатолий Иванович"));
  // => 1
  System.out.println(Validate("Стриженов-Бродский Анатолий"));
  // => 2
  System.out.println(Validate("Стриженов"));
  // => 0