带有捕获组的RegEx（不使用Java）[重复]

Question

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(.*SHELF)-(.*)\[.*SHELF-(.*)\]

Pattern pattern = Pattern.compile("(.*SHELF)-(.*)\\[.*SHELF-(.*)\\]");
Matcher matcher = pattern.matcher(inputString);
String group1 = matcher.group(1);
String group2 = matcher.group(2);
String group3 = matcher.group(3);

我得到以下错误：

java.lang.IllegalStateException: No match found

为什么会这样？

Answer 1

这篇文章回答了你最初的问题。

该表达式创建捕获组，并以多种形式返回所需的输出：

(([A-Z]+)-([0-9]+))\[([A-Z]+)-([A-Z0-9-]+)(\])

如果您愿意，您可以进一步简化它。

import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "(([A-Z]+)-([0-9]+))\\[([A-Z]+)-([A-Z0-9-]+)(\\])";
final String string = "PSHELF-2[PSHELF-MF-6RU]\n"
     + "SHELF-5[SHELF-M6]\n"
     + "SHELF-6[SHELF-M15]\n"
     + "SHELF-6[SHELF-M15]";
final String subst = "\\1 \\4";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);

// The substituted value will be contained in the result variable
final String result = matcher.replaceAll(subst);

System.out.println("Substitution result: " + result);

const regex = /(([A-Z]+)-([0-9]+))\[([A-Z]+)-([A-Z0-9-]+)(\])/gm;
const str = `PSHELF-2[PSHELF-MF-6RU]
SHELF-5[SHELF-M6]
SHELF-6[SHELF-M15]
SHELF-6[SHELF-M15]`;
const subst = `\nGroup 1: $1\nGroup 2: $2\nGroup3: $3\nGroup 4: $4\nGroup 5: $5`;

// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);

console.log('Substitution result: ', result);