Java中位数和平方根

Question

null

有更好的办法吗？

public static double []  berechneMittelwertWurzel(int startindex, int endindex) {
double arr[] = { 5.2, 66.23, -4.2, 0.0, 53.0 };
 double sum = 0;
 for(int i=0; i<arr.length; i++){
    sum = sum + arr[i];
  double average = sum / arr.length;
  
  for(int i =0; i < arr.length;i++)
  {
   for(int j = 0;j < arr.length;j++)
      {
          if(Math.sqrt(arr[i]) == arr[j])
          {
              s += arr[j] + "," + arr[i] + " ";
  if(index < 0 || index >= array.length)
      throw new IndexOutOfBoundsException();

Answer 1

您发布的函数不符合练习中的规范。存在各种各样的问题：

• 其参数错误
• 返回类型错误
• 它不检查参数或抛出指定的错误
• 您的函数似乎创建了一个字符串（分配给未声明的变量！）这对于解决问题是不必要的

另外，你的问题标题提到了中位数；但是，你试图计算算术平均值。从问题文本来看，这可能实际上是正确的。只是要注意这两个值通常是不同的。

public static double calculateMeanRoot(double[] array, int startindex, int endindex) {
    // if the startIndex > endIndex is an IntervalException should be thrown

    // if the endIndex > array.length -1 or startIndex < 0, the IndexOutOfBoundsException shall be thrown

    // calculate the sum of the array elements between `startIndex` and `endIndex` (*)

    // calculate the mean by dividing the sum by the difference between `endIndex` and `startIndex`

    // if the calculated mean is less than zero (<0), then a NegativeNumberException shall be thrown with an output

    // calculate the square root of the mean, round it, and return it
}