在Java中使用InputStreamReader时出错

Question

_port   = 8071;
_socket = new Socket("localhost", _port);

Random rand = new Random();
int  n = rand.nextInt(50) + 1;
DataOutputStream dos = new DataOutputStream(_socket.getOutputStream());
dos.writeInt(n);
dos.flush();

try {
    input = new BufferedReader(new InputStreamReader(socket.getInputStream()));

    ObjectInputStream in = null;
    in = new ObjectInputStream(socket.getInputStream());
    int ClientNumber= in.readInt();
    System.out.println(ClientNumber);
}

无效的流头:0000002b at java.io.objectinPutStream.ReadStreamHeader(ObjectinPutStream.java:781)at java.io.objectinPutStream.(ObjectinPutStream.java:278)at servicerEquest.run(servicerEquest.java:24)at java.util.concurrent.executors$runnableAdapter.call(executors.java:439)at java.util.concurrent.futureTask$sync.innerRun在java.util.concurrent.threadpoolexecutor$worker.run（threadpoolexecutor.java:895)，在java.lang.thread.run（thread.java:680)

有人知道是什么导致了错误吗？我的代码设置不当吗？

Answer 1

您使用DataOutputStream编写，使用ObjectInPutStream读取。您应该使用DataInputStream:

// Note declaration and assignment in a single statement. There's no point in
// making it null first.
DataInputStream in = new DataInputStream(socket.getInputStream());

// Note use of camelCase for variable name
int clientNumber = in.readInt();

在这里还应该去掉输入:您没有从中读取，而且由于这看起来像是二进制数据流，因此将其视为文本是不合适的。

哦，您应该在finally块中关闭输入流。