Regex验证逗号分隔的唯一数字列表

Question

• 2,4,6,7,1是有效输入。
• 2,2,6无效
• 2有效
• 2,无效
• 1,2,3,4,5,6,7,8无效（只有7个数字）

我尝试了^[1-7]（？：,[1-7])*$，但它接受重复的数字

var data = [
  '2,4,6,7,1',
  '2,2,6',
  '2',
  '2,',
  '1,2,3,2',
  '1,2,2,3',
  '1,2,3,4,5,6,7,8'
  ];
  
  data.forEach(function(str) {
    document.write(str + ' gives ' + /(?!([1-7])(?:(?!\1).)\1)^((?:^|,)[1-7]){1,7}$/.test(str) + '<br/>');
  });

Answer 1

编辑：

修正了重复数字不是第一个时的错误。

一种方法是：

^(?:(?:^|,)([1-7])(?=(?:,(?!\1)[1-7])*$))+$

^                               # Start of line
    (?:                         # Non capturing group
        (?:                     # Non capturing group matching:
            ^                   #  Start of line
            |                   # or
            ,                   #  comma
        )                       #
        ([1-7])                 # Capture digit being between 1 and 7
        (?=                     # Positive look-ahead
            (?:                 # Non capturing group
                ,               # Comma
                (?!\1)[1-7]     # Digit 1-7 **not** being the one captured earlier
            )*                  # Repeat group any number of times
            $                    # Up to end of line
        )                       # End of positive look-ahead
    )+                          # Repeat group (must be present at least once)
$                                # End of line

js lang-js prettyprint-override">var data = [
  '2,4,6,7,1',
  '2,2,6',
  '2',
  '2,',
  '1,2,3,4,5,6,7,8',
  '1,2,3,3,6',
  '3,1,5,1,8',
  '3,2,1'
  ];
  
  data.forEach(function(str) {
    document.write(str + ' gives ' + /^(?:(?:^|,)([1-7])(?=(?:,(?!\1)[1-7])*$))+$/.test(str) + '<br/>');
  });