狂饮6发送多部分数据

Question

我想向Guzzle Http请求添加一些数据。有文件名、文件内容和带有授权密钥的头。

$this->request = $this->client->request('POST', 'url', [
    'multipart' => [
        'name' => 'image_file',
        'contents' => fopen('http://localhost:8000/vendor/l5-swagger/images/logo_small.png', 'r'),
        'headers' =>
            ['Authorization' => 'Bearer uCMvsgyuYm0idmedWFVUx8DXsN8QzYQj82XDkUTw']
            ]]);

但我得到错误

可捕获的致命错误:传递给guzzle http \ PSR 7 \ multipart stream::add element()的参数2必须是数组类型，字符串给定，在vendor \ guzzle http \ PSR 7 \ src \ multipart stream . PHP的第70行调用，并在vendor \ guzzle http \ PSR 7 \ src \ multipart stream . PHP的第79行定义

在Guzzle 6中，文档是这样的：http://docs.guzzlephp.org/en/latest/request-options.html#multipart

谁知道我在哪里犯了错误？

Answer 1

试试这个为我工作

use GuzzleHttp\Client;
use GuzzleHttp\Psr7\Utils;

$this->client = new Client([
        'base_uri' => 'https://baseurl'
    ]);

$body = Utils::tryFopen($tempPath . $fileName, 'r');
$res = $this->client->request(
                 'POST',
                 'url',
                  [
                     'headers' => [
                        ...
                     ],
                     'body' => $body
                  ]
            );

Answer 2

以下是解决方案。具有访问令牌的标头应在多部分部分之外。

$this->request = $this->client->request('POST', 'request_url', [
            'headers' => [
                'Authorization' => 'Bearer access_token'
            ],
            'multipart' => [
                [
                    'Content-type' => 'multipart/form-data',
                    'name' => 'image_file',
                    'contents' => fopen('image_file_url', 'r')
                ]
            ]
        ]);

Answer 3

根据文档，“multipart的值是一个关联数组数组”，因此需要更深一层嵌套：

$this->request = $this->client->request('POST', 'url', [
    'multipart' => [
        [
            'name' => 'image_file',
            'contents' => fopen('http://localhost:8000/vendor/l5-swagger/images/logo_small.png', 'r'),
            'headers' => ['Authorization' => 'Bearer uCMvsgyuYm0idmedWFVUx8DXsN8QzYQj82XDkUTw']
        ]
    ]
]);