防止ProGuard混淆类成员名称

Question

public class ClassMultiPoints
 {
   public String message;
   public List<ClassPoints> data;

   public class ClassPoints
    {
      public String id;
      public List<ClassPoint> points;
      public class ClassPoint
       {
         public String speed;
         public String bearing;
       }
    }
 }

我尝试使用opoints.message。

当我在没有proguard的情况下运行应用程序时，应用程序运行成功。当我用proguard运行我的应用程序时，我的应用程序崩溃。

我认为问题是:proguard将我的类的属性'opoints.message'重命名为简短的'a'。

proguard.cfg:

-injars      bin/classes
-injars      libs
-outjars     bin/classes-processed.jar
-dontpreverify
-repackageclasses ''
-allowaccessmodification
-optimizations !code/simplification/arithmetic
-keepattributes *Annotation*
-dontskipnonpubliclibraryclasses
-optimizationpasses 5
-printmapping map.txt
-flattenpackagehierarchy

-keep public class * extends android.app.Activity
-keep public class * extends android.app.Application
-keep public class * extends android.app.MapActivity
-keep public class * extends android.app.Service
-keep public class * extends android.content.BroadcastReceiver
-keep public class * extends android.content.ContentProvider

-libraryjars  libs/commons-io-2.2.jar
-libraryjars  libs/ftp4j-1.7.1.jar
-libraryjars  libs/gson-2.2.2.jar

-keep public class org.apache.commons.io.**
-keep public class it.sauronsoftware.ftp4j.**
-keep public class com.google.gson.**

-keep public class com.mypackagename.ActivityMonitor$*

-keep public class * extends android.view.View {
    public <init>(android.content.Context);
    public <init>(android.content.Context, android.util.AttributeSet);
    public <init>(android.content.Context, android.util.AttributeSet, int);
    public void set*(...);
}

-keepclasseswithmembers class * {
    public <init>(android.content.Context, android.util.AttributeSet);
}

-keepclasseswithmembers class * {
    public <init>(android.content.Context, android.util.AttributeSet, int);
}

-keepclassmembers class * extends android.content.Context {
   public void *(android.view.View);
   public void *(android.view.MenuItem);
}

-keepclassmembers class * implements android.os.Parcelable {
    static android.os.Parcelable$Creator CREATOR;
}

-keepclassmembers class **.R$* {
    public static <fields>;
}

保留my one（静态）类的方法和属性的正确方法是什么？

Answer 1

如果不希望类成员被混淆，则使用GSON提供的serializedname注释。例如：

public class ClassMultiPoints
{
   @SerializedName("message")
   public String message;
   @SerializedName("data")
   public List<ClassPoints> data;

   ...

}

此外，请确保为Gson库添加适当的proguard配置。例如：

##---------------Begin: proguard configuration for Gson ----------
# Gson uses generic type information stored in a class file when working with
#fields. Proguard removes such information by default, so configure it to keep
#all of it.
-keepattributes Signature

# For using GSON @Expose annotation
-keepattributes *Annotation*

# Gson specific classes
-keep class sun.misc.Unsafe { *; }
#-keep class com.google.gson.stream.** { *; }

# Application classes that will be serialized/deserialized over Gson
-keep class com.google.gson.examples.android.model.** { *; }

##---------------End: proguard configuration for Gson ----------

欲知更多信息，请阅读本文。